Answer:
<u>x-intercept</u>
The point at which the curve <u>crosses the x-axis</u>, so when y = 0.
From inspection of the graph, the curve appears to cross the x-axis when x = -4, so the x-intercept is (-4, 0)
<u>y-intercept</u>
The point at which the curve <u>crosses the y-axis</u>, so when x = 0.
From inspection of the graph, the curve appears to cross the y-axis when y = -1, so the y-intercept is (0, -1)
<u>Asymptote</u>
A line which the curve gets <u>infinitely close</u> to, but <u>never touches</u>.
From inspection of the graph, the curve appears to get infinitely close to but never touches the vertical line at x = -5, so the vertical asymptote is x = -5
(Please note: we cannot be sure that there is a horizontal asymptote at y = -2 without knowing the equation of the graph, or seeing a larger portion of the graph).
Answer:
Step-by-step explanation:
We have the standard deviation for the sample, so we use the t-distribution to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 20 - 1 = 19
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 19 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 2.861.
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The format of the confidence interval is:
In which 
is the sample mean
So
Answer:
The answer to the expression is 8
The answer is C: x < -2
The fact that it is less than -2 is shown by the open circle on -2, and the arrow pointing to the left. An open circle means that the number cannot be included (which is why it can't be "less than or equal to," but instead is just "less than."), and the line pointing to the left means that your variable is specifically less than the number circled.
Mode is the number that occurs the most so here the mode is 56
