All categories

3 years ago

PLEASE HELP ME!!!!!!!

Mathematics

2 answers:

katrin [286]3 years ago

6 0

The answer is A, 50.24
Hope this helps

adell [148]3 years ago

4 0

Answer:

A. 50.24

Step-by-step explanation:

f(4) = 3.14 times 4²

f(4) = 3.14(16)

f(4) = 50.24

<h2><u><em>xoxo, </em></u></h2><h2><u><em>your highness...</em></u></h2>

You might be interested in

3.1 identifying equation of proportional relationships in graphs proportional relations answer

BigorU [14]

Answer:

lanera nose griego jaja xd

5 0

3 years ago

How do i factor this problem?

denpristay [2]

The problem is actually already factored for you. They are asking you to just set the equation to zero. Find the zeros.

8 0

3 years ago

Based only on the information given in the diagram, which congruence theorems or postulates could be given as reasons why ABC~DE

12345 [234]

Answer:- B , C and F are the right options.

Explanation:-

1. HA cannot be a reason to show given triangles are congruent as it is not given that they have an acute angle common in both the triangles.

2. HL can be a reason to show given triangles are congruent as the triangles are right triangle with equal legs and hypotenuse.

3. SAS can be a reason to show given triangles are congruent as there are two congruent sides in both triangles and included angles ∠A=∠D=90° [right angle].

4. LA cannot be a reason to show given triangles are congruent as it is not given that they have an acute angle common in both the triangles.

5. AAS cannot be a reason to show given triangles are congruent as it is not given that they have two angles common in both the triangles.

6.SSS can be a reason to show given triangles are congruent as it is shown that all the sides of one triangle is congruent to the other.

8 0

3 years ago

Read 2 more answers

(3y^0 x^2)^6 times y^-3 zx8

timurjin [86]

Ok so some basic rules

$(x^m)(x^n)=x^{m+n}$
$(ab)^c=(a^c)(b^c)$
$(x^m)^n=x^{mn}$
$x^0=1$
$x^{-m}= \frac{1}{x^m}$

so
$[(3y^0x^2)^6][y^{-3}zx^8]$
$[(3(1)x^2)^6][y^{-3}zx^8]$
$[(3x^2)^6][y^{-3}zx^8]$
$[(3^6)((x^2)^6)][y^{-3}zx^8]$
$[(3^6)(x^{12})][y^{-3}zx^8]$
$(3^6)(x^{12})(y^{-3})(z)(x^8)$
$(3^6)(x^{12})(x^8)(y^{-3})(z)$
$(3^6)(x^{20})(\frac{1}{y^3})(z)$
$\frac{3^6x^{20}z}{y^3}$
$\frac{729x^{20}z}{y^3}$

3 0

3 years ago

The number of users of the internet in a town increased by a factor of 1.01 every year from 2000 to 2010. The function below sho

Alex Ar [27]

Answer:

3000.(1.01)^x

Step-by-step explanation:

The domain is x greater or equal 0 (x must be a non-negative integer)

4 0

3 years ago