Answer:
Part A)
1) 
2) 
Part B)
1) 
2) 
Step-by-step explanation:
Part 1) x and y vary inversely and x=50 when y=5 find y when x=10 what is k?
we know that
A relationship between two variables, x, and y, represent an inverse variation if it can be expressed in the form 
or 
step 1
<u>Find the value of k</u>
x=50 when y=5
substitute the values
------> 
----->
The equation is equal to
or 
step 2
<u>Find y when x=10</u>
substitute the value of x in the equation and solve for y
Part B) x and y vary directly and x=6 when y=42 find k what is y when x=12
we know that
A relationship between two variables, x, and y, represent a direct variation if it can be expressed in the form 
or 
step 1
<u>Find the value of k</u>
x=6 when y=42
substitute the values
------> 
----->
The equation is equal to
or 
step 2
<u>Find y when x=12</u>
substitute the value of x in the equation and solve for y
Answer:
5=y-intercept
Step-by-step explanation:
the y intercept point is when y has a number but x is 0 so we see what is y (f(x)) and it is 5
Answer:
Step-by-step ef(x)=-2x+5……i
and f(-3x)=?
let x=-3x so that
-2x+5=-3x
x=5
substitutinx x into… i
f(x)=-10+5=-5
f(5)=-5………ii
now f(–3x)=f(-15)
scrutinizing… ii ,we can propose that
f(-15)=15.
Thus f(-3x)=15xplanation:
Answer:
add, subtract, multiply and divide complex numbers much as we would expect. We add and subtract
complex numbers by adding their real and imaginary parts:-
(a + bi)+(c + di)=(a + c)+(b + d)i,
(a + bi) − (c + di)=(a − c)+(b − d)i.
We can multiply complex numbers by expanding the brackets in the usual fashion and using i
2 = −1,
(a + bi) (c + di) = ac + bci + adi + bdi2 = (ac − bd)+(ad + bc)i,
and to divide complex numbers we note firstly that (c + di) (c − di) = c2 + d2 is real. So
a + bi
c + di = a + bi
c + di ×
c − di
c − di =
µac + bd
c2 + d2
¶
+
µbc − ad
c2 + d2
¶
i.
The number c−di which we just used, as relating to c+di, has a spec
Answer: 
Step-by-step explanation:
1. You have the following function given in the problem:
2. Then, to find 
asked in the exercise, you only need to substitute 
(which is the input value) into the given function.
3. Therefore, keeping the above on mind, you obtain that is:
