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3 years ago

What’s the answer for this I need help

Mathematics

2 answers:

Pavlova-9 [17]3 years ago

8 0

Answer:

18 ft²

Step-by-step explanation:

Area of the triangle: $\frac{1}{2}$ (1 × 4) = 2 ft

Area of the square: 4 × 4 = 16 ft

Add up the areas

You get 18 ft²

Rama09 [41]3 years ago

4 0

Answer:

18 ft^2

Step-by-step explanation:

4 x 4 = 16

4 x 1 = 4

4 / 2 = 2

16 + 2 = 18 ft.^2

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Jane’s cell phone plan is $40 each month plus $0.15 per minute for each minute over 200 minutes of call time. Janes cell phone b

san4es73 [151]

Answer:

The equation is $40+0.15m = 58.00$ whose solution is $m =120\:minutes.$

Step-by-step explanation:

Let us call $m$ the number of minutes the phone is used over 200 minutes, then we have

$\boxed{40+0.15m = 58.00}$ <em>(this says monthly bill of $40 plus the cost of phone usage over 200 minutes must equal $58 )</em>

This equation can be used to solve for $m$ u as follows:

$0.15m = 58-40$

$m = \dfrac{18}{0.15}$

$\boxed{m = 120\:minutes}$

8 0

3 years ago

If A, B, and C are mutually exclusive events with P(A) = 0.2, P(B) = 0.3, and P(C) = 0.4, determine the following probabilities:

fiasKO [112]

a. The events are mutually exclusive, so

$P(A\cup B\cup C)=P(A)+P(B)+P(C)=\boxed{0.9}$

b. For the same reason,

$P(A\cap B\cap C)=\boxed0$

Another way to see this is to use the result from part (a), and the inclusion/exclusion principle:

$P(A\cap B\cap C)=P(A)+P(B)+P(C)-P(A\cup B\cup C)$

and the right side reduces to 0.

c. Same as (b),

$P(A\cap B)=\boxed0$

d. Same as (b),

$P((A\cup B)\cap C)=\boxed0$

We can also use the distributivity rule for unions and intersections to write

$P((A\cup B)\cap C)=P((A\cap C)\cup(B\cap C))=P(A\cap C)+P(B\cap C)=0$

e. If the $A'$ is the complement of $A$ , then by DeMorgan's law,

$P(A'\cap B'\cap C')=P(A\cup B\cup C)'=1-P(A\cup B\cup C)=\boxed{0.1}$

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3 years ago

4x+y=7 in standard form

Marina86 [1]

Answer: Y=-4x+7

Explanation:

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4 years ago

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irina1246 [14]

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A. 1/3=24/72
B. 7/24=21/72
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7 0

4 years ago

Will give 12 points 2. At a fair, each person can spin two wheels of chance. The first wheel has the letters M and H. The second

Nookie1986 [14]

(a) M1, M2, M3, H1, H2 and H3.

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so probability = these outcomes / all possible outcomes
= 3/6 = 1/2 Answer

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4 years ago