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alex41 [277]
3 years ago
10

Will give 12 points 2. At a fair, each person can spin two wheels of chance. The first wheel has the letters M and H. The second

wheel has the numbers 1, 2, and 3.
(a) List all the possible outcomes of the compound event.


(b) If you spin both wheels, what is the probability that you get either an M or a 2? Explain.
Mathematics
1 answer:
Nookie1986 [14]3 years ago
8 0
(a)  M1,  M2,  M3,  H1,  H2 and H3.

(b) possible outcomes are M1, M3, H2.

so probability = these  outcomes / all possible outcomes
= 3/6  = 1/2 Answer
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We have two varieties of concrete that we can mix together. One is 5% water and 95% concrete mix, and the other is 20% water and
Orlov [11]

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  • <u>20 pounds</u> of the 95% concrete mix
  • <u>10 pounds</u> of the 80% concrete mix

=================================================

Explanation:

x = amount of the 95% concrete mix

y = amount of the 80% concrete mix

Type A mix has 95% concrete. If we have x pounds of this, then 0.95x pounds is pure concrete. Type B mix has 80% concrete. If there are y pounds of this, then 0.80y pounds is pure concrete.

So far we have 0.95x+0.80y pounds of pure concrete from the two mixes

Divide this over 30 to get (0.95x+0.80y)/30

Setting this equal to 0.90 means we want the final mix to be 90% concrete.

Since we want 30 pounds total, we can say x+y = 30 which solves to y = 30-x. We'll use this later

-------------------------------

(0.95x+0.80y)/30 = 0.90

0.95x+0.80y = 30*0.90 .... multiply both sides by 30

0.95x+0.80y = 27

0.95x+0.80(30-x) = 27 ..... plug in y = 30-x

0.95x+0.80*30-0.80*x = 27

0.95x+24-0.80x = 27

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0.15x = 27-24 ..... subtracting 24 from both sides

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x = 3/0.15 ........... dividing both sides by 0.15

x = 20

y = 30-x

y = 30-20

y = 10

5 0
3 years ago
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