Answer:
B: 2 mol NaOH/2 mol H2O
Explanation:
The reaction equation is;
H2SO4 + 2NaOH = Na2SO4 + 2H20
Now, to know how many moles of NaOH will be produced for 10.5 grams of water (H2O) used, and since the molar mass of H2O is 18.02 g/mol and number of moles attached to H2O and NaOH in the reaction are both 2 we will have;
10.5g H2O × 1 mol H2O/18.02 g H2O × 2 mol NaOH/2 mol H2O
Thus correct answer is option B
Answer:
The order of decreasing mass is: I - Fe-Mn- N
Explanation:
According to the periodic table the atomic masses of the elements of the statement are:
IODE (I): 126, 90447
IRON (Fe): 55,845
MANGANESE (Mn): 54, 938844
NITROGEN (N): 14, 0067
Answer:
Cuando Copérnico reemplazó la Tierra con el Sol en el centro del universo, cambió el papel de la astronomía en la sociedad. Gran parte de la resistencia a la teoría de Copérnico provino no solo de la comunidad científica, sino también como resultado de las implicaciones sociales de un universo heliocéntrico.
Explanation:
Espero que esto ayude a marcar el MÁS CEREBRAL !!!
M=2.65kg=2650g
M=74g/mol
n = m/M = 2650g/74g/mol ≈ 35.81mol
Heat of fusion = 7.27kJ/mol
If 7.27kJ ------------- energy is in --------------- 1mol
than x ------------- energy is in --------------- 35.81mol
x = [35.81mol*7.27kJ]/1mol = <u>260.3387kJ</u>
hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:
En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )
where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:
En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )
where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.hydrogen-like ion is an ion containing only one electron. The energy of the electron in a hydrogen-like ion is given by:
En = −(2.18 × 10^−18J) Z^2 ( 1/n^2 )
where n is the principal quantum number and Z is the atomic number of the element. Plasma is a state of matter consisting of positive gaseous ions and electrons. In the plasma state, a mercury atom could be stripped of its 80 electrons and therefore could exist as Hg80+. Use the equation above to calculate the energy required for the last ionization step.
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