Answer: <span>Molecular geometry around each carbon atom in a saturated hydrocarbon is
Tetrahedral.
Explanation: </span> In saturated hydrocarbons (-CH₂-) the central atom (
carbon) is bonded to either three or two hydrogen atoms and one or two carbon atoms. So, the central atom is having four electron pairs and all pairs are bonding pairs and lacks any lone pair of electron. According to
Valence Shell Electron Pair Repulsion (VSEPR)
Theory the central atom with four bonding pair electrons and zero lone pair electrons will attain a
tetrahedral geometry with
bond angles of 109°.
Answer:
It would decrease
Explanation:
As temperature decreases the particles in the gas have less kinetic energy and therefore have less energy to overcome the bonds that hold them together and slowly move closer. Furthermore, increased pressure forces them to move closer to each other, decreasing the volume
Why does the moon and the sun have the same mass?
Answer: The difference is that, on the moon, you are much lighter than on the Earth, but you still have the same mass
The new volume at standard temperature and pressure is 5.08 L.
Explanation:
As per the kinetic theory of gases, the volume occupied by gas molecules will be inversely proportional to the pressure of the gas molecules. This is termed as Boyle's law.
So, pressure∝
Thus, if two pressure and two volumes are given then,

Now, we known the values of P₁ = 8 atm, V₁ = 635 mL, P₂ = 1 atm and V₂ we have to determine. We are considering P₂ = 1 atm, because we have to determine V₂ at standard temperature and pressure. And standard pressure is 1 atm.

Thus, the new volume at standard temperature and pressure is 5.08 L.