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3 years ago

Can someone help me with these three Chemistry questions?

Chemistry

1 answer:

Xelga [282]3 years ago

8 0

There are 6 molecules of Mg3(PO4)2
6 × 3 = 18 Mg
6 × 4 × 2 = 48 O

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Reversible reaction and examples on them

Tomtit [17]

Answer:

Here are three examples

Explanation:

In a reversible reaction, the conversions of reactants to products and of products to reactants occur at the same time.

Example 1

The reaction of hydrogen and iodine to from hydrogen iodide.

H₂ + I₂ ⇌ 2HI

Example 2

The dissociation of carbonic acid in water to form hydronium and hydrogen carbonate ions

H₂CO₃ + H₂O ⇌ H₃O⁺ + HCO₃⁻

Example 3

The dissociation of dinitrogen tetroxide to nitrogen dioxide.

N₂O₄ ⇌ 2NO₂

4 0

3 years ago

The electronic configuration of an element is given below.

drek231 [11]

Answer:

C. It is reactive because it must gain two electrons to have a full outermost energy level.

Step-by-step explanation:

The electron configuration of this element ends in 2s²2p⁴.

A filled energy level would end in 2s²2p⁶.

The element will be reactive, because it must gain electrons to have a full energy level, and it needs two more electrons to do this.

4 0

3 years ago

Which is the larger atom kr Or As

nasty-shy [4]

Answer:

I think As is larger

Explanation:

5 0

2 years ago

Write the balanced equation for the reaction of aqueous Pb ( ClO 3 ) 2 with aqueous NaI . Include phases. chemical equation: Wha

Citrus2011 [14]

<u>Answer:</u> The mass of lead iodide produced is 9.22 grams

<u>Explanation:</u>

To calculate the molarity of solution, we use the equation:

$\text{Molarity of the solution}=\frac{\text{Moles of solute}}{\text{Volume of solution (in L)}}$

Molarity of NaI = 0.200 M

Volume of solution = 0.200 L

Putting values in above equation, we get:

$0.200M=\frac{\text{Moles of NaI}}{0.200}\\\\\text{Moles of NaI}=(0.200mol/L\times 0.200L)=0.04moles$

The chemical equation for the reaction of NaI and lead chlorate follows:

$Pb(ClO_3)_2(aq.)+2NaI(aq.)\rightarrow PbI_2(s)+2NaClO_3(aq.)$

By Stoichiometry of the reaction:

2 moles of NaI reacts produces 1 mole of lead iodide

So, 0.04 moles of NaI will react with = $\frac{1}{2}\times 0.04=0.02mol$ of lead iodide

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Molar mass of lead iodide = 461 g/mol

Moles of lead iodide= 0.02 moles

Putting values in above equation, we get:

$0.02mol=\frac{\text{Mass of lead iodide}}{461g/mol}\\\\\text{Mass of lead iodide}=(0.02mol\times 461g/mol)=9.22g$

Hence, the mass of lead iodide produced is 9.22 grams

6 0

3 years ago

The process in which rock fragments freeze to the bottom of a glacier and then are carried away when the glacier moves is called

guapka [62]

Im pretty sure its called plucking

3 0

3 years ago

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