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IgorC [24]
3 years ago
8

One mole of aluminum atoms has a mass of 27 grams. How many grams are in 9.0 moles of aluminum?

Chemistry
1 answer:
gizmo_the_mogwai [7]3 years ago
6 0
27*9=243 if one mole is equal to 27 grams times that by 9
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Determine the approximate amount of potassium hydrogen phthalate, KHP, that you will need to neutralize 6.00 ml of 0.100 M NaOH.
Sveta_85 [38]

Answer:

potassium hydrogen phthalate KHP MOLAR MASS = 204.233 glmol

to get 1000 ml

Molar concentration = Mass concentration/Molar Mass

mass concentration = molar concentration x molar mass

mass concentration=0.1 M,

molar mass= 204.233 g/mol

so to get 1L

mass conc = 204.233 x 0.1

= 20.4233g  for 1L or 1000 ml

to get 6.00 ml

if 20.4233g is for 1000ml

then to 6.00 ml

= 20.4233 x 6 / 1000

= 0.123g for 6.00 ml

according to the equation below

NaOH(aq) + KHC8H4O4(aq) --> KNaC8H4O4(aq) + H2O(l)

number of moles of NaOH is equal to that of KHP

so the same amount will be needed too, which is

= 0.123g

6 0
3 years ago
How many grams of barium sulfate, BaSO 4 , be precipitated when 2.25 moles of sodium sulfate , Na 2 SO 3 , reacts with an excess
gulaghasi [49]

Answer:

525.1 g of BaSO₄ are produced.

Explanation:

The reaction of precipitation is:

Na₂SO₄ (aq) + BaCl₂ (aq) →  BaSO₄ (s) ↓  +  2NaCl (aq)

Ratio is 1:1. So 1 mol of sodium sulfate can make precipitate 1 mol of barium sulfate.

The excersise determines that the excess is the  BaCl₂.

After the reaction goes complete and, at 100 % yield reaction, 2.25 moles of BaSO₄ are produced.

We convert the moles to mass: 2.25 mol . 233.38 g/mol = 525.1 g

The precipitation's equilibrium is:

SO₄⁻² (aq)  +  Ba²⁺ (aq)  ⇄  BaSO₄ (s) ↓       Kps

7 0
3 years ago
There are 154,000 mg of sugar in a
Kipish [7]

Explanation:

1g = 1000mg

154000mg = 154g

No of days she can drink = 154÷ 11 = 14days

5 0
3 years ago
Period, block, and group
Sedaia [141]

Answer:

what do you mean

Explanation:

8 0
3 years ago
What is the name of CH=CH2 ​
Strike441 [17]

Answer:

CH2 is the chemical name for methylene and belongs to the general compound category of Alkenes. It comprises of a single carbon atom bonded with 2 hydrogen atoms . The general formula for alkenes is C(n)H(2n) with n denoting the number of carbon atoms and thus deciding the name of the compound.

Explanation:

4 0
3 years ago
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