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IgorC [24]
3 years ago
8

One mole of aluminum atoms has a mass of 27 grams. How many grams are in 9.0 moles of aluminum?

Chemistry
1 answer:
gizmo_the_mogwai [7]3 years ago
6 0
27*9=243 if one mole is equal to 27 grams times that by 9
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How many grams of tris (mw 121.1) would you need to prepare 100 ml of a 100 mm tris solution? _________ grams?
Tems11 [23]

Molarity = (Mass/ molar mass) x (1/ volume of solution in Litres)

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Molarity of Tris = 100 mM = 0.1 M

volume of Tris sol. = 100 mL = 0.1 L

molar mass of Tris = 121.1 g/mol

Hence,

mass of Tris = Molarity of Tris x molar mass ofTris x volume of Tris solution

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= 1.211 g

mass of Tris = 1.211 g


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Paha777 [63]

Answer:

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