Answer:
<h2>25m²</h2>
Step-by-step explanation:
If you want to find the area, you have to use this formula:
Formula:
LxW
L: length
W: Width
Here we have a square, and the sides are all 5 meters long, that means that we have to just do 5x5 to get the answer.
5x5=?
Hope ya remember the 5 table, lol, I know everyone does
5x5=25
so hence, your answer is 25m²
Thanks!
Answered by: FieryAnswererGT
#learnwithbrainly
A would be the correct answer because the y variable only has a coefficient of 1. So we would solve for y, which would get us y=3x+5, then we would substitute the value in the second equation which would look like -4x+5(3x+5)=58. Hope this helpss. :)
Answer:
Final answer is
.
Step-by-step explanation:
Given problem is
.
Now we need to simplify this problem.
![\sqrt[3]{x}\cdot\sqrt[3]{x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D)
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D)
Apply formula
![\sqrt[n]{x^p}\cdot\sqrt[n]{x^q}=\sqrt[n]{x^{p+q}}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Bx%5Ep%7D%5Ccdot%5Csqrt%5Bn%5D%7Bx%5Eq%7D%3D%5Csqrt%5Bn%5D%7Bx%5E%7Bp%2Bq%7D%7D)
so we get:
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{1+2}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D%3D%5Csqrt%5B3%5D%7Bx%5E%7B1%2B2%7D%7D)
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=\sqrt[3]{x^{3}}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D%3D%5Csqrt%5B3%5D%7Bx%5E%7B3%7D%7D)
![\sqrt[3]{x^1}\cdot\sqrt[3]{x^2}=x](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7Bx%5E1%7D%5Ccdot%5Csqrt%5B3%5D%7Bx%5E2%7D%3Dx)
Hence final answer is
.
Answer:
48
Step-by-step explanation:
10+5+18+15
pls mark brainliest
Answer:
The midpoint of A and B is (0, 4).
Step-by-step explanation:
Use the midpoint formula, ((x₁ + x₂)/2 , (y₁ + y₂)/2)
First, solve for the x part.
(2 + (-2))/2
0/2
0
So the x-coordinate of the midpoint is 0.
Then, solve for the y part.
(3 + 5)/2
8/2
4
So the y-coordinate of the midpoint is 4.