The statement, "Julian's sister said he walked 1/5 mile" cannot be agreed because Julian totally walked 
miles.
<u>Solution:</u>
Given that,
- Julian walked 6/10 of a mile to his friends house
- Another 35/100 mile to the store
- He walked 1/4 of a mile back home
To find total distance walked by Julian we have to add the above stated values. That is, 
Factors of 10 = 
Factors of 100 = 
Factors of 4 = 
Therefore, the least common factor of 10, 100 and 4 is 100. With like denominators we can operate on just the numerators,
Which can also be written as 
.
So, from the above calculation it can be said that Julian walked 
.
Answer:
Step-by-step explanation:
M + P + C = 13.5
6M + 3P + C = 48.50
OM + 2P - C = O
2P = C
Therefore, there are 6 pounds of meat, 2.5 pounds of potatoes, and 5 pounds of carrots.
Answer:
6.25n + 3.50
$34.75
Step-by-step explanation:
Break down the important information given in the problem.
The one-time delivery fee is 3.50. This is only paid one time an never again, making it the <u>constant</u>, a number that does not change.
Each lunch costs 6.25. This amount will increase depending on how many times Mr. Jackson orders lunches, "n" times. This number is the <u>rate</u> because it changes. The rate is attached to the variable.
If you add the amounts together, that is the total cost of ordering lunches.
6.25n + 3.50
(Reember expressions do not have the equal sign).
To find the cost of ordering 5 lunches, use the expression. Substitute "n" for 5 because "n" represents the number of lunches ordered.
6.25n + 3.50
= 6.25(5) + 3.50 Simplify by multiplying 5 and 6.25
= 31.25 + 3.50 Add the two values
= 34.75 Total cost of 5 lunches
Therefore the cost of ordering 5 lunches is $34.75.
Answer:
Option C and D are examples of associative property of multiplication.
Option A is examples of commutative property of multiplication.
Option B is normal multiplication.
Hope this helps!
:)
