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zzz [600]
3 years ago
11

As the value of the slope gets smaller the graph of a line gets

Mathematics
2 answers:
irina1246 [14]3 years ago
8 0

Answer:

Less steep

Step-by-step explanation:

xxTIMURxx [149]3 years ago
4 0
As the valeof the slope get smaller the graph of the line gets less steep
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If a parallelogram has congruent
o-na [289]

Answer: A

Step-by-step explanation:

The contrapositive of a statement is logically equivalent to the original statement.

6 0
2 years ago
The following table shows scores obtained in an examination by B.Ed JHS Specialism students. Use the information to answer the q
Makovka662 [10]

Answer:

(a) The cumulative frequency curve for the data is attached below.

(b) (i) The inter-quartile range is 10.08.

(b) (ii) The 70th percentile class scores is 0.

(b) (iii) the probability that a student scored at most 50 on the examination is 0.89.

Step-by-step explanation:

(a)

To make a cumulative frequency curve for the data first convert the class interval into continuous.

The cumulative frequencies are computed by summing the previous frequencies.

The cumulative frequency curve for the data is attached below.

(b)

(i)

The inter-quartile range is the difference between the third and the first quartile.

Compute the values of Q₁ and Q₃ as follows:

Q₁ is at the position:

\frac{\sum f}{4}=\frac{100}{4}=25

The class interval is: 34.5 - 39.5.

The formula of first quartile is:

Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h

Here,

l = lower limit of the class consisting value 25 = 34.5

(CF)_{p} = cumulative frequency of the previous class = 24

f = frequency of the class interval = 20

h = width = 39.5 - 34.5 = 5

Then the value of first quartile is:

Q_{1}=l+[\frac{(\sum f/4)-(CF)_{p}}{f}]\times h

     =34.5+[\frac{25-24}{20}]\times5\\\\=34.5+0.25\\=34.75

The value of first quartile is 34.75.

Q₃ is at the position:

\frac{3\sum f}{4}=\frac{3\times100}{4}=75

The class interval is: 44.5 - 49.5.

The formula of third quartile is:

Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h

Here,

l = lower limit of the class consisting value 75 = 44.5

(CF)_{p} = cumulative frequency of the previous class = 74

f = frequency of the class interval = 15

h = width = 49.5 - 44.5 = 5

Then the value of third quartile is:

Q_{3}=l+[\frac{(3\sum f/4)-(CF)_{p}}{f}]\times h

     =44.5+[\frac{75-74}{15}]\times5\\\\=44.5+0.33\\=44.83

The value of third quartile is 44.83.

Then the inter-quartile range is:

IQR = Q_{3}-Q_{1}

        =44.83-34.75\\=10.08

Thus, the inter-quartile range is 10.08.

(ii)

The maximum upper limit of the class intervals is 69.5.

That is the maximum percentile class score is 69.5th percentile.

So, the 70th percentile class scores is 0.

(iii)

Compute the probability that a student scored at most 50 on the examination as follows:

P(\text{Score At most 50})=\frac{\text{Favorable number of cases}}{\text{Total number of cases}}

                                 =\frac{10+4+10+20+30+15}{100}\\\\=\frac{89}{100}\\\\=0.89

Thus, the probability that a student scored at most 50 on the examination is 0.89.

5 0
3 years ago
Find the area. Will mark brainliest.
erik [133]

Answer:

8

Step-by-step explanation:

The equation for the area of a parallelogram is A=bh. In this case, the base is 4 and the height is two so the equation would be 4*2 which would be eight.

3 0
3 years ago
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The map shows the location of the airport and a warehouse in a city. Though not displayed on the map, there is also a factory 10
kipiarov [429]

step 1

find the coordinates of the factory

the factory is 104 miles due north of the warehouse

the coordinates of the warehouse are (39,-52)

coordinates of the factory------> (39,-52+104)------> (39,52)

step 2

find the distance warehouse to airport

let

A coordinates of warehouse-------> A( 39,-52)

B coordinates of airport---------> B(-39,52)

C coordinates of factory-------> C(39,52)

distance AB=√[(52+52)²+(-39-39)²]------> distance AB=130 miles

step 3

find the distance airport to factory

B(-39,52)

C(39,52)

distance BC=√[(52-52)²+(39+39)²]-----> distance BC=39 miles

the total number of miles=distance AB+distance BC---> 130+39

the total number of miles=169 miles

<em>Thus</em> the answer is 169

4 0
2 years ago
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Which phrase best describes f(x), graphed on the coordinate plane below? On a coordinate plane, a curve goes through two cycles.
igomit [66]

Answer:

5.6

Step-by-step explanation:

7 0
3 years ago
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