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charle [14.2K]
3 years ago
13

Cada pregunta y complete con V si considera que la aseveración es verdadera y una F si considera que es falsa (15 puntos total)(

1 punto c/u)
1 ___ Al resolver un sistema de ecuación lineal 2X2 se obtiene siempre un punto de intersección entre las dos ecuaciones lineales.
2 ____ Existe solo un método para resolver sistema de ecuaciones lineales 2x2.
3 ____ Un sistema de ecuaciones lineales 2x2 puede tener infinitas soluciones.
4 _____ Los sistemas de ecuaciones líneas se pueden resolver utilizando el método de igualación.
5 _____ El método de reducción consiste en despejar en una de las dos ecuaciones una de las tres incógnitas y sustituirla en la nueva ecuación.
6 _____ Al aplicar una homotecia en el plano cartesiano la figura solo aumenta o disminuye de tamaño.
7 _____ Al aplicar homotecia a una figura esta mantiene su forma.
8 _____ Las tablas de doble entrada nos permiten organizar la información.
9 _____ Las potencias sirven para escribir una multiplicación formada por varios números iguales de una manera más simplificada.
10 _____ La representación grafica de una función cuadrática es una parábola.
11 _____ La concavidad de una parábola lo determina el término independiente.
12 _____ El eje de simetría es una línea recta horizontal que divide a la parábola en dos.
13 _____ En probabilidades el espacio muestra corresponde a todas las posibles soluciones.
14 _____En probabilidades dos eventos son independientes ya que la realización de uno no afecta la probabilidad del otro.
15 _____ En la función cuadrática las soluciones son siempre dos soluciones distintas.
Mathematics
2 answers:
Natali [406]3 years ago
5 0

Answer:

sey

Step-by-step explanation:

natima [27]3 years ago
3 0

Step-by-step explanation:

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The value of the digit 4 in the number 6,028,468 is 100
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Tina bought some nail polish and lip gloss at the store. The nail polish cost $4.50 per bottle and lip gloss cost $7 per tube, T
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The graph of a sinusoidal function has a minimum point at (0,3)(0,3) and then intersects its midline at (5π,5)
bekas [8.4K]

Answer: F(x) = 2*sin(x/10  +(3/2)*pi) + 5

Step-by-step explanation:

The information that we have is that:

We have a minimum at (0, 3)

the midline is at (5*pi, 5)

This is a sinusoidal function, so we can write one generic one as:

F(x) = A*sin(c*x + p) + B.

where A and B are constants, c is the frequency and p is a phase

First, the minimum of the sine function is when sin(x) = -1, and this happens at (3/2)*pi

We know that this minimum is at x = 0.

sin(c*0 + p) = -1

Then p = 3/2*pi.

So our function is:

F(x) = A*sin(c*x  +(3/2)*pi) + B.

Now, we know that F(0) = 3, so:

3 = A*sin(c*0 +(3/2)*pi) + B = -A + B.

now we can use the other hint, the midpoint of the sine function is when sin(x) = 0, and this happens at x = 0 and x = pi, particularlly as we here have a phase of 3/2*pi, we should find x = 2*pi.

then:

c*5*pi + (3/2)*pi = 2*pi

c*5 + 3/2 = 2

c*5 = 2 - 3/2 = 1/2

C = 1/2*5 = 1/10

So our function is

F(x) = A*sin(x/10  +(3/2)*pi) + B

and we know that when x = 5*pi, F(5*pi) = 5, so:

5 = F(x) = A*sin(5*pi/10  +(3/2)*pi) + B

5 = B

and we aready knew that:

- A + B = 3

-A + 5 = 3

A = 5 - 3 = 2

So our equation is:

F(x) = 2*sin(x/10  +(3/2)*pi) + 5

8 0
4 years ago
Suppose that an airline uses a seat width of 16.5 in. Assume men have hip breadths that are normally distributed with a mean of
Alexxx [7]

Answer:

a) 0.018

b) 0            

Step-by-step explanation:

We are given the following information in the question:

Mean, μ =  14.4 in

Standard Deviation, σ = 1 in

We are given that the distribution of breadths is a bell shaped distribution that is a normal distribution.

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\sigma}

a) P(breadth will be greater than 16.5 in)

P(x > 16.5)

P( x > 16.5) = P( z > \displaystyle\frac{16.5 - 14.4}{1}) = P(z > 2.1)

= 1 - P(z \leq 2.1)

Calculation the value from standard normal z table, we have,  

P(x > 16.5) = 1 - 0.982 = 0.018 = 1.8\%

0.018 is the probability that if an individual man is randomly​ selected, his hip breadth will be greater than 16.5 in.

b) P( with 123 randomly selected​ men, these men have a mean hip breadth greater than 16.5 in)

Formula:

z_{score} = \displaystyle\frac{x-\mu}{\frac{\sigma}{\sqrt{n}}}  

P(x > 16.5)  

P( x > 16.5) = P( z > \displaystyle\frac{16.5-14.4}{\frac{1}{\sqrt{123}}}) = P(z > 23.29)  

= 1 - P(z \leq 23.29)

Calculation the value from standard normal z table, we have,  

P(x > 16.5) = 1 - 1 = 0

There is 0 probability that 123 randomly selected men have a mean hip breadth greater than 16.5 in

4 0
3 years ago
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