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charle [14.2K]
3 years ago
13

Cada pregunta y complete con V si considera que la aseveración es verdadera y una F si considera que es falsa (15 puntos total)(

1 punto c/u)
1 ___ Al resolver un sistema de ecuación lineal 2X2 se obtiene siempre un punto de intersección entre las dos ecuaciones lineales.
2 ____ Existe solo un método para resolver sistema de ecuaciones lineales 2x2.
3 ____ Un sistema de ecuaciones lineales 2x2 puede tener infinitas soluciones.
4 _____ Los sistemas de ecuaciones líneas se pueden resolver utilizando el método de igualación.
5 _____ El método de reducción consiste en despejar en una de las dos ecuaciones una de las tres incógnitas y sustituirla en la nueva ecuación.
6 _____ Al aplicar una homotecia en el plano cartesiano la figura solo aumenta o disminuye de tamaño.
7 _____ Al aplicar homotecia a una figura esta mantiene su forma.
8 _____ Las tablas de doble entrada nos permiten organizar la información.
9 _____ Las potencias sirven para escribir una multiplicación formada por varios números iguales de una manera más simplificada.
10 _____ La representación grafica de una función cuadrática es una parábola.
11 _____ La concavidad de una parábola lo determina el término independiente.
12 _____ El eje de simetría es una línea recta horizontal que divide a la parábola en dos.
13 _____ En probabilidades el espacio muestra corresponde a todas las posibles soluciones.
14 _____En probabilidades dos eventos son independientes ya que la realización de uno no afecta la probabilidad del otro.
15 _____ En la función cuadrática las soluciones son siempre dos soluciones distintas.
Mathematics
2 answers:
Natali [406]3 years ago
5 0

Answer:

sey

Step-by-step explanation:

natima [27]3 years ago
3 0

Step-by-step explanation:

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4) Write the equation of the line graphed<br> below.
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2 years ago
In 2008, the average household debt service ratio for homeowners was 13.2. The household debt service ratio is the ratio of debt
ankoles [38]

Answer:

t=\frac{13.88-13.2}{\frac{3.14}{\sqrt{44}}}=1.436    

df=n-1=44-1=43  

p_v =P(t_{(43)}>1.436)=0.079  

We see that the p value i higher than the significance level so then we FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly higher than 13.2 *the value of 2008 ).

Step-by-step explanation:

Information given

\bar X=13.88 represent the sample mean

s=3.14 represent the sample standard deviation

n=44 sample size  

\mu_o =13.2 represent the value that we want to test

\alpha=0.05 represent the significance level

t would represent the statistic (variable of interest)  

p_v represent the p value for the test

Hypothesis to test

We want to conduct a hypothesis in order to check if the true mean has increased from 2008 , and the system of hypothesi are:  

Null hypothesis:\mu \leq 13.2  

Alternative hypothesis:\mu > 13.2  

The statistic for this case is:

t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}  (1)  

Calculating the statistic

Replacing the info given we got:

t=\frac{13.88-13.2}{\frac{3.14}{\sqrt{44}}}=1.436    

P-value

The degrees of freedom are:

df=n-1=44-1=43  

Since is a right tailed test the p value is:  

p_v =P(t_{(43)}>1.436)=0.079  

Decision

We see that the p value i higher than the significance level so then we FAIL to reject the null hypothesis and we can conclude that the true mean is not significantly higher than 13.2 *the value of 2008 ).

8 0
3 years ago
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