The set when z = -5 is {-27, -9, -5}
<h3>How to determine the set elements?</h3>
The set is given as:
{(4z-7,z-4,z) |z is any real number}
When z=-5, we have:
4z - 7 = 4(-5) - 7 = -27
z - 4 = -5 - 4 = -9
z = -5
So, we have:
{(4z-7,z-4,z) |z is any real number} ⇒ {-27, -9, -5}
Hence, the set when z = -5 is {-27, -9, -5}
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Answer: 7x5x4=140^3
140
Step-by-step explanation:
U add 6 to every number each time
5,11,17,23,29,35,41,47,53,59,65,71,78,84,90,96,101,108
108 is the 18th term
Minus 1 both sides
x²-8x=-1
take 1/2 of the linear coefient and square it
-8 is the linear coefient
-8/2=-4, (-4)²=16
add 16 to both sides
x²-8x+16=16-1
factor perfect squaer trinomial
(x-4)²=15
square root both sides, remember to take positive and negative roots
x-4=+/-√15
not exactly sure what to put in the blnaks
but
the solutions are x=4+√15 and x=4-√15
The answer is 2 2/5. Need an explanation
