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stepladder [879]

3 years ago

13

Suppose that, from measurements in a microscope, you determine that a certain bacterium covers an area of 1.50μm2. Convert this

to square meters.

1 answer:

galben [10]3 years ago

7 0

1 m = 1 x 10⁶ μm
1 m² = (1 x 10⁶)² μm²
1 m² = 1 x 10¹² μm²

area = 1.5 / 1 x 10¹² m²
Area = 1.5 x 10⁻¹² m²

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Juan went to the store to buy a plant for his mother, but forgot to ask which kind to get. Out of 30 plants, eighteen of them ar

Luba_88 [7]

Answer:

Probability [Randomly choose plant Juan's mother want] = 3 / 5

Step-by-step explanation:

Given:

Total number of plant in store = 30 plants

Number of plant kind Juan's mother want = 18

Find:

Probability [Randomly choose plant Juan's mother want]

Computation:

Probability of an event = Number of favorable outcome / Total number of outcomes

Probability [Randomly choose plant Juan's mother want] = Number of plant kind Juan's mother want / Total number of plant in store

Probability [Randomly choose plant Juan's mother want] = 18 / 30

Probability [Randomly choose plant Juan's mother want] = 3 / 5

7 0

3 years ago

Use the coordinate grid to determine the coordinates of point A;

ser-zykov [4K]

A (1 1/4, -3/4)

answer is B. second choice

5 0

3 years ago

Read 2 more answers

B= c= Please help asap

gladu [14]

B= 20°
and c = 160°

b is equal to the given angle, b = 20°

c is 180 - 20 = 160°

4 0

2 years ago

Let represent the number of tires with low air pressure on a randomly chosen car. The probability distribution of is as follows.

Sindrei [870]

Answer:

a) $P(X=3) = 0.1$

b) $P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

c) $P(X=4) = 0.3$

d) $P(X=0) = 0.2$

e) $E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

f) $E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

Step-by-step explanation:

We have the following distribution

x 0 1 2 3 4

P(x) 0.2 0.3 0.1 0.1 0.3

Part a

For this case:

$P(X=3) = 0.1$

Part b

We want this probability:

$P(X\geq 3) =1-P(X$

And replacing we got:

$P(X \geq 3) = 1- [0.2+0.3+0.1]= 0.4$

Part c

For this case we want this probability:

$P(X=4) = 0.3$

Part d

$P(X=0) = 0.2$

Part e

We can find the mean with this formula:

$E(X)= \sum_{i=1}^n X_i P(X_i)$

And replacing we got:

$E(X) =0*0.2 +1*0.3+2*0.1 +3*0.1 +4*0.3= 2$

Part f

We can find the second moment with this formula

$E(X^2)= \sum_{i=1}^n X^2_i P(X_i)$

And replacing we got:

$E(X^2) =0^2*0.2 +1^2*0.3+2^2*0.1 +3^2*0.1 +4^2*0.3= 6.4$

And the variance would be:

$Var(X0 =E(X^2)- [E(X)]^2 = 6.4 -(2^2)= 2.4$

And the deviation:

$\sigma =\sqrt{2.4} = 1.549$

4 0

3 years ago

Determine the value of x in the figure below.<br><br> x =

Marianna [84]

Answer:

116

Step-by-step explanation:

16+16=56/2=4

5 0

2 years ago