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2 years ago

Find the slope of the line that contains the points (4,20) and (6,-4)

Mathematics

1 answer:

Y_Kistochka [10]2 years ago

4 0

Slope = (y2-y1) / (x2-x1)
= (-4-20) / (6-4)
= (-24) / (2)
= (-12)

The slope of the line is (-12)

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Answer:

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Step-by-step explanation:

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svetoff [14.1K]

<h2>Hello!</h2>

The answer is: $g(x)=-\sqrt[3]{x-1}$

Let's check the roots and the shown point in the graphic (2,-1)

First,

$0=-\sqrt[3]{x-1}\\\\0^{3}=(-\sqrt[3]{x-1})^{3}\\\\0=-(x-1)\\\\x=1$

then,

$g(0)=-\sqrt[3]{0-1}\\g(0)=-(-1)\\g(0)=1\\y=1$

So, we know that the function intercepts the axis at (1,0) and (0,1), meaning that the function match with the last given option

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Second,

Evaluating the function at (2,-1)

$y=-\sqrt[3]{x-1}\\-1=-\sqrt[3]{2-1}\\-1=-\sqrt[3]{1}\\-1=-(1)\\-1=-1$

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It means that the function passes through the given point.

Hence,

The equation which represents g(x) is $g(x)=-\sqrt[3]{x-1}$

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3 years ago

What is the solution to x/3 = -12

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Step-by-step explanation:

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