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ss7ja [257]
3 years ago
5

A road has a scale of 1:50 000 The length of a road on the map is 8.5cm.Work out the length of the real road in kilometres

Mathematics
1 answer:
ozzi3 years ago
5 0

Answer:

ok so

8.5*150000

1275000 cm into kilometers is

12.75 kilometers

Hope This Helps!!!

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Which answer shows line segments that are perpendicular to each other? Two parallel line segments with parallel symbol, no arrow
velikii [3]

Two intersecting line segments forming an angle marked with a small box.

The "small box" represents 90°, and perpendicular lines are 2 intersecting lines that form 90° angles

4 0
4 years ago
Ramona reads 18 books from the library each month for y months in a row. Write an expression to show how many books Ramona read
Licemer1 [7]

Answer:

The answer to your question is:

Step-by-step explanation:

Data

Books read = 18

y = number of months

a ) Expression

                                  R(y) = 18 y

b) Number of books read after 10 months

     

                                R(10) = 18(10)

                               R(10) = 180 books

7 0
4 years ago
The value root of 40 of lies between which two consecutive integers
pychu [463]

When you square  +6  or  -6  you get  36.  That's less than  40.

When you square  +7  or  -7, you get  49.  That's more than  40.

So one of the square roots of  40  is between  <em>+6  and  +7</em>, and
the other square root of  40  is between  <em>-7  and  -6 </em>.


4 0
4 years ago
220-109.4 how to solve ?
anastassius [24]

Answer: 110.6

Step-by-step explanation: 220 - 109.4 = 110.6

7 0
3 years ago
Read 2 more answers
Use the given transformation to evaluate the integral.
GuDViN [60]

For the transformation

\begin{cases}x=7u+v\\y=u+7v\end{cases}

the Jacobian is

\dfrac{\partial(x,y)}{\partial(u,v)}=\begin{bmatrix}7&1\\1&7\end{bmatrix}

with determinant

\det\left(\begin{bmatrix}7&1\\1&7\end{bmatrix}\right)=48

The vertices of the triangle in the u,v-plane are

(x,y)=(0,0)\implies(u,v)=(0,0)

(x,y)=(7,1)\implies(u,v)=(1,0)

(x,y)=(1,7)\implies(u,v)=(0,1)

Then the integral is

\displaystyle\iint_R(x-8y)\,\mathrm dA=-48\int_0^1\int_0^{1-v}(u+55v)\,\mathrm du\,\mathrm dv=\boxed{-448}

3 0
3 years ago
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