Question

Alloy C is made from some part of Alloy A and Alloy B. Alloy C, which weighs 400 ounces and has 40% aluminum, is obtained from melting together x ounces of Alloy A, which has 30% aluminum, and y ounces of Alloy B, which has 60% aluminum. Which equation will help find how many of ounces of each alloy A and alloy B are used to make Alloy C? Question 10 options: A+B=4000.3A+0.55B=0.4(400) A+B=40030A+55B=0.4(400) A+B=400.3A+0.55B=400 A+B=4000.3A+0.55B=400

Answer 1

Answer:

I suppose correct opton is option A, but all options are for 55% alloy B

Step-by-step explanation:

Alloy A (30%):

Weight = x ounces

Weight of aluminium $=0.3\cdot x=0.3x$ ounces

Alloy B (60%):

Weight = y ounces

Weight of aluminium $=0.6\cdot y=0.6y$ ounces

Alloy C (40%):

Weight = 400 ounces

Weight of aluminium $=0.4\cdot 400$ ounces

The weight of alloy C is combined weight of alloys A and B, then

$x+y=400$

The weight of aluminium in alloy C is combined weight of aluminium in alloys A and B, then

$0.3x+0.6y=0.4\cdot 400$