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3241004551 [841]
3 years ago
12

What is the solution to the system of equations -8x + 4y = -2, 2y = 1​

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
5 0

Answer:

Hi! The correct answer is x=1/4+y/2!

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation

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If ΔLMN ≅ ΔOPR, m∠L = (x^2 - x)°, m∠P = 16°, m∠N = (4x+160)°. Find m∠R.
Marizza181 [45]

Answer:

mZR = (4x + 160)°

Step-by-step explanation:

cause, mZR = mZN

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8 0
3 years ago
What is the simplified form of the quantity of x plus 7, all over 2 − the quantity of x plus 4, all over 2?
astraxan [27]

(x + 7)/2 - (x + 4)/2 = (x + 7 - (x + 4)/2 = (x + 7 - x - 4)/2 = 3/2

7 0
3 years ago
Plz help plz plz plz plz
inysia [295]
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The answer is 15.
8 0
3 years ago
Read 2 more answers
There are 150 oranges, apples and pears in a box. The ratio of the number of oranges to the number of apples is 3:5 and the rati
Rom4ik [11]

Answer:

  Pears:  30

Step-by-step explanation:

Constant:

  3x + 5x + 2x = 150

                 10x = 150

                    x = 15  

Multiply ratio with constant from above:

  oranges : apples

       3 * 15 : 5 * 15

            45 : 75       ==>               45 oranges: 75 apples

  pears : apples

   2 * 15 : 5 * 15

        30 : 75          ==>                    30 pears: 75 apples

Check:

45 oranges + 75 apples + 30 pears = 150 fruits

4 0
3 years ago
At which points are the tangents drawn to the ellipse x 2 + y 2 = [ a ] x + [ a ] y parallel to
In-s [12.5K]

The given equation of the ellipse is x^2 + y^2 = 2 x + 2 y

At tangent line, the point is horizontal with the x-axis therefore slope = dy / dx = 0

<span>So we have to take the 1st derivative of the equation then equate dy / dx to zero.</span>

x^2 + y^2 = 2 x + 2 y

x^2 – 2 x = 2 y – y^2

(2x – 2) dx = (2 – 2y) dy

(2x – 2) / (2 – 2y) = 0

2x – 2 = 0

x = 1

 

To find for y, we go back to the original equation then substitute the value of x.

x^2 + y^2 = 2 x + 2 y

1^2 + y^2 = 2 * 1 + 2 y

y^2 – 2y + 1 – 2 = 0

y^2 – 2y – 1 = 0

Finding the roots using the quadratic formula:

y = [-(- 2) ± sqrt ( (-2)^2 – 4*1*-1)] / 2*1

y = 1 ± 2.828

y = -1.828 , 3.828

 

<span>Therefore the tangents are parallel to the x-axis at points (1, -1.828) and (1, 3.828).</span>

3 0
3 years ago
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