Tanya run 50 yards across the diagonal of the rectangular field.
<u>Step-by-step explanation</u>:
Step 1 :
- Length of the rectangular field = 40 yards
- width of the rectangular field = 30 yards
Step 2 :
Measure of the diagonal = √(length^2 + width^2 )
Step 3 :
Diagonal = √(40^2 + 30^2 )
= √(1600 + 900)
= √2500
= ±50
Step 4 :
Since distance cannot be negative, The measure of diagonal = 50 yards.
∴ Tanya runs diagonally across a rectangular field is 50 yards.
Actually Welcome to the Concept of the Trigonometry.
here, we use the Linear pair property of the adjacent angles.
We know that, all the adjacent angles in a linear pair add to get 180°
so we get as,
=> (n+6) +90°+(2n+3) =180°
=> (n+6) +(2n+3) =180-90
=> 3n+9 = 90
=> 3n= 90-9
=> 3n = 81
hence, n = 81/3
=> n = 27°
thus the value of n is 27° .
Answer:
The answer is 2(the square root of 65 )
Step-by-step explanation:
Plug ( -6, 2) and (8, 10) into the distance formula and solve.
Distance = the square root of ((x2 - x1)^2 + (y2 - y1)^2))
Distance = the square root of ((8 - -6)^2 + (10 - 2)^2))
Distance = the square root of (14^2 + 8^2)
Distance = the square root of (196 + 64)
Distance = the square root of 260 which can be simplified to 2(the square root of 64)
Answer:
a = 6/5
b = 7/8
c = 1/5
Step-by-step explanation:
We want to make two of these equations be in terms of the same variable, so let's solve the first and third in terms of b.
5a-24b=-15 -> -3 + 24b/5 = a
48b+35c = 49 -> 49/35 - 48b/35 = 7/5 - 48b/35 = c
Now we can replace the a and c in the second equation and solve for b.
10a+45c=21
10(-3+24b/5)+45(7/5 - 48b/35) = 21
-30 + 48b + 63 - 432b/7 = 21 -> -12 = -96b/7 -> b=7/8
Now we can plug b back into the other two to solve for a and c. I will leave that to you unless you would like the steps there.
