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3241004551 [841]
3 years ago
12

What is the solution to the system of equations -8x + 4y = -2, 2y = 1​

Mathematics
1 answer:
Black_prince [1.1K]3 years ago
5 0

Answer:

Hi! The correct answer is x=1/4+y/2!

Step-by-step explanation:

Solve for the first variable in one of the equations, then substitute the result into the other equation

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What is the compound inequality
navik [9.2K]
This should be anegative decrease
6 0
3 years ago
Michael bought 160 hotdogs were eating competition he spends $240 an hour how much did each hotdog cost
geniusboy [140]

Answer:

$1.50

Step-by-step explanation:

1. we know that its $240 per 160 hot dogs

2. make that a ratio - 240:160

3. simplify the ratio so that the amount of hot dogs is at one (so divide both sides by 160)

4. so 240/160 = 1.5 .   160/160 = 1

5. 1.5:1

6. so for every one hotdog, you pay $1.50

4 0
4 years ago
The cost of a week long vacation in a city has a mean of 1000 and a variance of 1200. The city imposes a tax which will raise al
matrenka [14]

Answer:

The coefficient of variation after the tax is imposed is 0.033

Step-by-step explanation:

Given

\mu =1000 --- mean

\sigma^2 = 1200 --- variance

tax = 10\%

Required

The coefficient of variation

The coefficient of variation is calculated using:

CV = \frac{\sqrt{\sigma^2}}{\mu}

After the tax, the new mean is:

\mu_{new} = \mu * (1 + tax)

\mu_{new} = 1000 * (1 + 10\%)

\mu_{new} = 1100

And the new variance is:

\sigma^2_{new} = \sigma^2 * (1 + tax)

\sigma^2_{new} = 1200 * (1 + 10\%)

\sigma^2_{new} = 1320

So, we have:

CV = \frac{\sqrt{\sigma^2}}{\mu}

CV = \frac{\sqrt{1320}}{1100}

CV = \frac{36.33}{1100}

CV = 0.033

6 0
3 years ago
Number 15. Find the equation of the line that passes through (3,-1) and is perpendicular to the line that passes through (-5, 2)
MArishka [77]
For lines to be perpendicular their slopes must be negative reciprocals of one another, mathematically:

m1*m2=-1

So we first need to find the slope of the reference line.

m=(y2-y1)/(x2-x1)=(7-2)/(-1--5)=5/4

So the perpendicular line will have a slope of:

5m/4=-1

m=-4/5

So our perpendicular line so far is:

y=-4x/5+b, now we can use point (3,-1) to solve for the y-intercept, "b"

-1=-4(3)/5+b

-1=-12/5+b

-5/5+12/5=b

7/5=b

So the line is:

y=-4x/5+7/5 or more neatly

y=(-4x+7)/5

y=-0.8x+1.4
3 0
3 years ago
. To graph the equation, first plot 5 points on the graph: one point with =x0 , two points with negative x -values, and two poin
TEA [102]
K (this has to be 20 characters long so I am typing this)
3 0
3 years ago
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