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3 years ago

What is the equation of a line through the points (0, 9) and (3, 0)?

Mathematics

2 answers:

erastova [34]3 years ago

7 0

Answer:

m = StartFraction 9 minus 0 Over 0 minus 3 EndFraction; y = –3x + 9

Step-by-step explanation:

The given points are the y-intercept and the x-intercept, so they can be used directly in the intercept form of the equation of a line.

x/(x-intercept) +y/(y-intercept) = 1

x/3 +y/9 = 1

Multiplying by 9 gives ...

3x +y = 9

This can be rearranged to the slope-intercept form ...

y = -3x +9

_____

The answer selection shown above is the only one that matches the slope and y-intercept of the line through the given points.

kakasveta [241]3 years ago

4 0

Answer:

because m = StartFraction 9 minus 0 Over 0 minus 3 EndFraction; y = –3x + 9

Step-by-step explanation:

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Instructions:Select the correct answer. What is the nth term of the geometric sequence 4, 8, 16, 32, ... ?

Minchanka [31]

4, 8, 16, 32, 64, 128, 256, 512, 1,024.

1,024 is the ninth number in this geometric sequence.

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3 years ago

4x-5y+2z=-3<br> 6x+4y+9z=8<br> 11x-2y-z=7

Nutka1998 [239]

Answer:

thank you i need that

Step-by-step explanation:

4 0

3 years ago

The area of the base of the oblique pentagonal pyramid is 50 cm^2 and the distance from the apex to the center of the pentagon i

Verdich [7]

The complete question in the attached figure

Part a)
we know that
ABC is a right triangle
∠ACB=45°
AC=hypotenuse------> 6√2 cm
sin 45=AB/AC-----> AB=AC*sin 45----> AB=6√2*√2/2----> AB=6 cm

the answer part a) is
AB=6 cm

Part b)
we know that
volume of the pyramid=(1/3)*Area of the base*height
area of the base=50 cm²
height=6 cm
so
volume of the pyramid=(1/3)*50*6----> 100 cm³

the answer part b) is
100 cm³

5 0

3 years ago

(2x - y + 3) (2x - y - 3)using identities

Tems11 [23]

Step-by-step explanation:

(2x-y+3)(2x-y-3)=

4x²-2xy-6x-2xy+y²+3y+6x-3y-9=

4x²-4xy+y²-9=

(2x-y)²-9

6 0

3 years ago

For all values of x

Yuliya22 [10]

Answer:

A.) gf(x) = 3x^2 + 12x + 9

B.) g'(x) = 2

Step-by-step explanation:

A.) The two given functions are:

f(x) = (x + 2)^2 and g(x) = 3(x - 1)

Open the bracket of the two functions

f(x) = (x + 2)^2

f(x) = x^2 + 2x + 2x + 4

f(x) = x^2 + 4x + 4

and

g(x) = 3(x - 1)

g(x) = 3x - 3

To find gf(x), substitute f(x) for x in g(x)

gf(x) = 3( x^2 + 4x + 4 ) - 3

gf(x) = 3x^2 + 12x + 12 - 3

gf(x) = 3x^2 + 12x + 9

Where

a = 3, b = 12, c = 9

B.) To find g '(12), you must first find the inverse function of g(x) that is g'(x)

To find g'(x), let g(x) be equal to y. Then, interchange y and x for each other and make y the subject of formula

Y = 3x + 3

X = 3y + 3

Make y the subject of formula

3y = x - 3

Y = x/3 - 3/3

Y = x/3 - 1

Therefore, g'(x) = x/3 - 1

For g'(12), substitute 12 for x in g' (x)

g'(x) = 12/4 - 1

g'(x) = 3 - 1

g'(x) = 2.

5 0

3 years ago