Answer:
Your answer should be K=21.7
You can find this by subtracting 26.2-4.5
The perimeter of the first figure is 34 cm and the area is 64 cm².
The perimeter of the second figure is 38 cm and the area is 60 cm².
The perimeter of the third figure is 30 cm and the area is 36 cm².
The perimeter of the fourth figure is 72 cm and the area is 200 cm².
The perimeter of the fifth figure is 30 cm and the area is 36 cm².
To find the perimeter of each, we add the area of all sides. For the first figure, the missing sides are 1 cm and 6 cm. To find the area, we have two rectangles whose dimensions are 6x10 and 1x4.
For the second figure, the missing sides are 4 cm and 3 cm. To find the area, we have two rectangles whose dimensions are 4x12 and 3x4.
For the third figure, the missing sides are 3 cm, 3 cm and 8 cm. To find the area, we have two rectangles whose dimensions are 4x3 and 3x8.
For the fourth figure, the missing sides are 10 cm, 10 cm, 6 cm and 6 cm. To find the area, we have two squares whose dimensions are 10x10.
For the fifth figure, the missing sides are 3 cm and 9 cm. To find the area, we have two rectangles whose dimensions are 3x6 and 6x3.
I will solve you system by substitution
y = 2x - 3 ; x + y = 1
→Step 1: Solve y = 2x - 3 for y
→Step 2: Substitute 2x - 3 for y in x + y = 1:
x + y = 1
x + 2x- 3 = 1
3x - 3 = 1 (Simplify both sides of the equation)
3x - 3 + 3 = 1 + 3 (Add 3 both sides)
3x = 4
3x ÷ 3 = 4 ÷ 3 (Divide each side by 3)
x = 4/3
→Step 3: Substitute 4/3 for x in y = 2x - 3:
y = 2x - 3
y = 2 (4/3) -3
y = -1/3 (Simplify both sides of the equation)
Answer:
x = 4/3 and y = -1/3
∫Hope that helps∫
Answer:
Since the leading coefficient is negative and the exponent is to a degree of 4...
The graph will be down on both ends.
Answer:
The solutions are the points (-3,0) and (-1,-2)
Step-by-step explanation:
we have
-----> equation A
-----> equation B
Solve the system of equations by graphing
The solution of the system of equations are the intersection points both graphs
The solutions are the points (-3,0) and (-1,-2)
see the attached figure
