Answer:
hi! you can use desmos graphing calculator to help you graph these- just look it up and plug the equation in. its nice for future use as well.
Step-by-step explanation:
and no , (5,10) isn't a solution to the equation because it falls under x≥2 but not under y<x+3. Hope this helps !
Answer:
a=-13
Step-by-step explanation:
16−5a+2a−1=41−a
16-1-41 = 5a-2a-a
-26 = 2a
a= -26/2
a=-13
Answer:
The worth of the car after 6 years is £2,134.82
Step-by-step explanation:
The amount at which Dan buys the car, PV = £2200
The rate at which the car depreciates, r = -0.5%
The car's worth, 'FV', in 6 years is given as follows;
![FV = PV \cdot \left ( 1 + \dfrac{r}{100} \right )^n](https://tex.z-dn.net/?f=FV%20%3D%20PV%20%5Ccdot%20%5Cleft%20%28%201%20%2B%20%5Cdfrac%7Br%7D%7B100%7D%20%5Cright%20%29%5En)
Where;
r = The depreciation rate (negative) = -0.5%
FV = The future value of the asset
PV = The present value pf the asset = £2200
n = The number of years (depreciating) = 6
By plugging in the values, we get;
![FV = 2200 \times \left ( 1 + \dfrac{-0.5}{100} \right )^6 \approx 2,134.82](https://tex.z-dn.net/?f=FV%20%3D%202200%20%5Ctimes%20%5Cleft%20%28%201%20%2B%20%5Cdfrac%7B-0.5%7D%7B100%7D%20%5Cright%20%29%5E6%20%5Capprox%202%2C134.82)
The amount the car will be worth which is its future value, FV after 6 years is FV ≈ £2,134.82 (after rounding to the nearest penny (hundredth))
Answer:
u=-2
Step-by-step explanation:
Let's solve your equation step-by-step.
11u=−22
Step 1: Divide both sides by 11.
11u
11
=
−22
11
u=−2
Answer:
u=−2
Answer:
∠XDQ : 41°
∠UXD: 139 °
Step-by-step explanation:
Allow me to rewrite your answer for a better understanding and please have a look at the attached photo.
<em>A segment XD is drawn in rectangle QUAD as shown below.
</em>
<em>What are the measures of ∠XDQ and ∠UXD ?
</em>
My answer:
As we can see in the photo, ∠ADX = 49° and ∠ADU =90°
=> ∠XDQ = ∠ADU - ∠ADX
= 90° - 49° = 41°
In the triangle ADX, we can find out the angle of ∠DXA
= 180° - ∠DAX - ∠ADX
= 180° - 90° - 49°
= 41°
=> <em>∠UXD = </em>180° - ∠DXA (Because UA is a straight line)
=180° - 41°
= 139 °