Y=2x-1 3x+5y=34 X= Y=

Mathematics

1 answer:

andreyandreev [35.5K]3 years ago

7 0

5+y=6y 3+x=4x =6y+4y=34 now that is as far as I can go

You might be interested in

Please help

AVprozaik [17]

I personally think it's C I hope it's right if not I'm Sorry

6 0

3 years ago

Find vÌ, the orthogonal projection of v onto w. you can't enter vÌ as a variable name in matlab, so call it vbar instead. also c

lubasha [3.4K]

Jjjjjjjjjjjjjjjjjjjj

8 0

3 years ago

HELP NEEDED ASASP

Maurinko [17]

Answer:

Jamie has a foot plank that he needs to cut into 1/9 pieces.

15 ÷ 1/9 = 135

135 x 1/9 = 15

Step-by-step explanation:

4 0

2 years ago

Whats the answer to 21g-6f-8g

Mkey [24]

21g-6f-8g
13g-6f is the answer
combine like terms

7 0

3 years ago

A research team at Cornell University conducted a study showing that approximately 10% of all businessmen who wear ties wear the

LenKa [72]

Answer:

a) The probability that at least 5 ties are too tight is P=0.0432.

b) The probability that at most 12 ties are too tight is P=1.

Step-by-step explanation:

In this problem, we could represent the proabilities of this events with the Binomial distirbution, with parameter p=0.1 and sample size n=20.

a) We can express the probability that at least 5 ties are too tight as:

$P(x\geq5)=1-\sum\limits^4_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\geq5)=1-(0.1216+0.2702+0.2852+0.1901+0.0898)\\\\P(x\geq5)=1-0.9568=0.0432$

The probability that at least 5 ties are too tight is P=0.0432.

a) We can express the probability that at most 12 ties are too tight as:

$P(x\leq 12)=\sum\limits^{12}_{k=0} {\frac{n!}{k!(n-k)!} p^k(1-p)^{n-k}}\\\\P(x\leq 12)=0.1216+0.2702+0.2852+0.1901+0.0898+0.0319+0.0089+0.0020+0.0004+0.0001+0.0000+0.0000+0.0000\\\\P(x\leq 12)=1$

The probability that at most 12 ties are too tight is P=1.

5 0

3 years ago