The limit of the given function if
is 64
<h3>Limit of a function</h3>
Given the following limit of a function expressed as;

We are to determine the value of the function
![\frac{1}{4} \lim_{x \to 0} [f(x)]^4](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%20%20%5Clim_%7Bx%20%5Cto%200%7D%20%5Bf%28x%29%5D%5E4)
This can also be expressed as
![\frac{1}{4} \lim_{x \to 0} [f(x)]^4\\ = \frac{1}{4}(4)^4 \\=1/4\times 256\\=64](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B4%7D%20%20%5Clim_%7Bx%20%5Cto%200%7D%20%5Bf%28x%29%5D%5E4%5C%5C%20%3D%20%5Cfrac%7B1%7D%7B4%7D%284%29%5E4%20%5C%5C%3D1%2F4%5Ctimes%20256%5C%5C%3D64)
Hence the limit of the given function if
is 64
Learn more on limit of a function here: brainly.com/question/23935467
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Answer:
I think it would be 12440
Step-by-step explanation:
Please give me brainliest
N is the variable, you solve by subtracting 6 from 20, getting n = 14.
<span>We have the yearly cost in dollars y at a video game arcade based on total game tokens purchased

. So we know that:
</span>

<span>
</span>

<span>
</span><span>
Then we can study this problem by using the graph in the figure below. We know that if there's no any purchase, the yearly cost for a
member will be $60 and for a
nonmember there will not be any cost. From this, we can affirm that the cost of membership is equal to $60.
On the other hand, both members and nonmembers will pay the same price on the total game tokens purchased, this is true because of the same slope that members and nonmembers have in the equations.</span>
Answer:
Let d be the remaining distance.
Let t be the remaining time.
The standard distance equation is:
d = rt
We are given the rate as 2, so:
d = 2t
At the start of the walk, the remaining distance is 3 miles.
The remaining time is 1.5 hours.
At the end of the walk, the remaining distance is 0 miles.
The remaining time is 0 hours.
A graph of the distance and time would be a continuous, solid line. That's because the walker will be at every distance between 3 and 0 and every time between 1.5 and 0.
Answer:
The graph of this would be a solid line