Question

C++Assign to maxSum the max of (numA, numB) PLUS the max of (numY, numZ). Use just one statement. Hint: Call FindMax() twice in an expression.#include using namespace std;double FindMax(double num1, double num2) { double maxVal; // Note: if-else statements need not be understood to complete this activity if (num1 > num2) { // if num1 is greater than num2, maxVal = num1; // then num1 is the maxVal. } else { // Otherwise, maxVal = num2; // num2 is the maxVal. } return maxVal;}int main() { double numA; double numB; double numY; double numZ; double maxSum; cin >> numA; cin >> numB; cin >> numY; cin >> numZ; /* Your solution goes here */ cout << "maxSum is: " << maxSum << endl; return 0;}

Answer 1

Answer:

Replace the comment with:

maxSum =FindMax(numA,numB)+FindMax(numY,numZ);

Explanation:

Required

The statement to add up the two maximum from the functions

To do this, we have to call FindMax for both arguments i.e.

FindMax(numA,numB) and FindMax(numY,numZ) respectively

Next, use the + sign to add up the returned value.

So, the complete statement is:

maxSum =FindMax(numA,numB)+FindMax(numY,numZ);

See attachment for complete program