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valkas [14]
3 years ago
9

Find two consecutive even integers who's sum is 34.

Mathematics
1 answer:
aleksklad [387]3 years ago
3 0

Answer:

Step-by-step explanation:

Let the smaller integer be x

x+x+2 =34

2x+2=34

2x=32

x=16

Smaller even integer = 16

Larger even integer = 16+2 = 18

Answer = 16,18

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Find the median and mode of this set of data 5 , 1, 3, 5, 8 , 10, 8, 14
kobusy [5.1K]

Answer:

Mode: 5 and 8

Median: 6.5

Step-by-step explanation:

Mode - the number that appears the most in a set of data. There may be no mode ( when no number out numbers the others)  or multiple modes ( multiple numbers appear the same number of times). Both 5 and 8 appear twice in this set.

Median - The middle number. To start, order your numbers from least to greatest.

1, 3, 5, 5, 8, 8, 10, 14

You have an even set of numbers (8 in total), which means there won't be one number left in the middle. In this situation, there are two: 5 and 8. So you just need to add them together and divide by 2

8 + 5 = 13        

13/ 2 = 6.5

3 0
3 years ago
Read 2 more answers
Artaud noticed that if he takes the opposite of his age and adds 45 he gets the number 32. How old is Artaud?
elena-14-01-66 [18.8K]

Answer:

He is 13 years old

Step-by-step explanation:

32-45=-13

the opposite of -13 is positive 13

3 0
3 years ago
Given: △ABC, m∠A=60° m∠C=45°, AB=8 Find: Perimeter of △ABC, Area of △ABC . FIRST CORRECT ANSWER GETS POINTS AND BRAINLIEST!!!! T
Ad libitum [116K]

Answer:

Given : In △ABC, m∠A=60°, m∠C=45°,and AB=8 unit

Firstly, find the angles B

Sum of measures of the three angles of any triangle equal to the straight angle, and also expressed as 180 degree

∴m∠A+ m∠B+m∠C=180                      ......[1]

Substitute the values of m∠A=60° and m∠C=45° in [1]

60^{\circ}+ m\angle B+45^{\circ}=180^{\circ}

105^{\circ}+ m\angle B=180^{\circ}

Simplify:

m\angle B=75^{\circ}

Now, find the sides of BC

For this, we can use law of sines,

Law of sine rule is an equation relating the lengths of the sides of a triangle  to the sines of its angles.

\frac{\sin A}{BC} = \frac{\sin C}{AB}

Substitute the values of ∠A=60°, ∠C=45°,and AB=8 unit to find BC.

\frac{\sin 60^{\circ}}{BC} =\frac{\sin 45^{\circ}}{8}

then,

BC = 8 \cdot \frac{\sin 60^{\circ}}{\sin 45^{\circ}}

BC=8 \cdot \frac{0.866025405}{0.707106781} =9.798 unit

Similarly for  AC:

\frac{\sin B}{AC} = \frac{\sin C}{AB}

Substitute the values of ∠B=75°, ∠C=45°,and AB=8 unit to find AC.

\frac{\sin 75^{\circ}}{AC} =\frac{\sin 45^{\circ}}{8}

then,

AC = 8 \cdot \frac{\sin 75^{\circ}}{\sin 45^{\circ}}

AC=8 \cdot \frac{0.96592582628}{0.707106781} =10.9283 unit

To find the perimeter of triangle ABC;

Perimeter = Sum of the sides of a triangle

i,e

Perimeter of △ABC = AB+BC+AC = 8 +9.798+10.9283 = 28.726 unit.

To find the area(A) of triangle ABC ;

Use the formula:

A = \frac{1}{2} \times AB \times AC \times \sin A

Substitute the values in above formula to get area;

A=\frac{1}{2} \times 8 \times 10.9283 \times \sin 60^{\circ}

A = 4 \times 10.9283 \times 0.86602540378

Simplify:

Area of triangle ABC = 37.856 (approx) square unit





4 0
3 years ago
Divide these polynomials. (8x³ + 2x² - 7x + 2) ÷ (2x - 1)
Novay_Z [31]

Answer:

The answer is letter A.

(8x³ + 2x² - 7x + 2) ÷ (2x - 1)

8x³ + 2x² - 7x + 2 ÷ 2x - 1

(2x-1)(4x²+3x-2)÷2x-1

cancel 2x-1 so that the answer is 4x²+3x-2.

6 0
3 years ago
Simplify the following expression:<br><br> -3(x+6)+8x<br> 3x-25<br> 5x-22<br> -11+3x<br> 5x-18
Alina [70]

Answer:

5x -18

<h2>I hope this helped! </h2><h3>have a nice day! :)</h3>
3 0
3 years ago
Read 2 more answers
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