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never [62]
2 years ago
11

is it possible to draw a pair of supplementary angles in which both angles are acute. Explain your Answer with words and drawing

s
Mathematics
1 answer:
tiny-mole [99]2 years ago
8 0

It is practically impossible to draw a pair of supplementary angles in which both angles are acute.

<h3>What are Supplementary Angles?</h3>

When two angles add up to give us 180 degrees, both angles are said to be supplementary angles. Thus, they have a sum of 180 degrees. One is a supplement of the other.

<h3>What are Acute Angles?</h3>

Acute angles can be defined as angles that have a measure that is less than 90 degrees. That is, they do not measure up to 90 degrees or have a measure below 90 degrees.

Thus, this means that, for two angles to be supplementary, one of them can be an acute angle while the other must be more than 90 degrees. For example, 50 degrees is an acute angle while 130 degrees is not an acute angle, but they are supplementary angles because: 50 + 130 = 180°.

On the other hand, the sum of two acute angles cannot be equal to 180 degrees. E.g, 89 + 89 = 178°.

In conclusion, it is therefore, practically impossible to draw a pair of supplementary angles in which both angles are acute.

Learn more about supplementary angles on:

brainly.com/question/8992900

#SPJ1

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In triangle ABC, angle A is congruent to angle C, AB= 10x-7, BC= 2x+33 And AC= 4x-6. Find x
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Since <A is congruent to <C , so triangle ABC is an isoceles triangle and side AB is congruent to BC.

AB = BC

Therefore, we can set up an equation as following:

10x - 7 = 2x + 33

10x - 7 - 2x = 2x + 33 -2x Subtracting 2x from each sides.

8x -7 = 33

8x - 7 + 7 = 33 + 7 Add 7 to each sides.

8x = 40

\frac{8x}{8} =\frac{40}{8} Divide each sides by 40.

So, x = 5

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