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Ksenya-84 [330]

3 years ago

10

Part A The year in which the US Civil War ended was 25 percent later than the year Christopher Columbus set sail from Spain. If

c represents the year Columbus set sail, we can write the year the Civil War ended as C +0.25c. Rewrite this expression as a single term.

1 answer:

IRINA_888 [86]3 years ago

3 0

Answer:

0.25 c to the second

Step-by-step explanation:

i think

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In Asad's class, 4/5 of the students like cake. Of those, 2/3 like chocolate cake. What ftaction of Asad's class likes chocolate

abruzzese [7]

4/5 * 2/3 = 8/15

Option A., less than 2/3.

7 0

3 years ago

Colt1911 [192]

Answer:

The correct answer is C. y = 3/4x - 12

Step-by-step explanation:

In order to find this, we must first note that the slope will be 3/4. We can tell this because parallel lines have the same slope. Next, we use that along with the point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - -18 = 3/4(x - -8)

y + 18 = 3/4 (x + 8)

y + 18 = 3/4x + 6

y = 3/4x - 12

4 0

3 years ago

Consider the sequence {4,6,8,10,...} find the 130th term of the sequence

Olin [163]

262

Step-by-step explanation:

Step 1:

To find the nth term of a sequence the basic formula is

Sn = (n*d) + (a-d)

Whereas

Sn= nth Term

n= Term to be found

d= Difference between the terms in the sequence

a= First term in the sequence

Step 2:

Sn = (130*2) +(4-2)

= 260+2

Sn= 262

The nth term for the given problem is 262

3 0

3 years ago

You must design a closed rectangular box of width w, length l and height h, whose volume is 504 cm3. The sides of the box cost 3

Charra [1.4K]

Answer:

Dimensions will be

Length = 7.23 cm

Width = 7.23 cm

Height = 9.64 cm

Step-by-step explanation:

A closed box has length = l cm

width of the box = w cm

height of the box = h cm

Volume of the rectangular box = lwh

504 = lwh

$h=\frac{504}{lw}$

Sides which involve length and width and height, cost = 3 cents per cm²

Top and bottom of the box costs = 4 cents per cm²

Cost of the sides $C_{s}$ = 3[2(l + w)h] = 6(l + w)h

$C_{s}$ = 3[2(l + w)h]

$C_{s}=6(l+w)(\frac{504}{lw} )$

Cost of the top and the bottom $C_{(t,p)}$ = 4(2lw) = 8lw

Total cost of the box C = $3024\frac{(l+w)}{lw}$ + 8lw

= $3024[\frac{1}{l}+\frac{1}{w}]$ + 8lw

To minimize the cost of the sides

$\frac{dC}{dl}=3024(-l^{-2}+0)+8w=0$

$\frac{3024}{l^{2}}=8w$

$\frac{378}{l^{2}}=w$ ---------(1)

$\frac{dC}{dw}=3024(-w^{-2})+8l=0$

$\frac{3024}{w^{2}}=8l$

$\frac{378}{w^{2}}=l$

$w^{2}=\frac{378}{l}$ -------(2)

Now place the value of w from equation (1) to equation (2)

$(\frac{378}{l^{2}})^{2}=\frac{378}{l}$

$\frac{(378)^{2} }{l^{4}}=\frac{378}{l}$

l³ = 378

l = ∛378 = 7.23 cm

From equation (2)

$w^{2}=\frac{378}{7.23}$

$w^{2}=52.28$

w = 7.23 cm

As lwh = 504 cm³

(7.23)²h = 504

$h=\frac{504}{(7.23)^{2}}$

h = 9.64 cm

6 0

4 years ago

If f(x) = x is changed to g(x) = -f(x + 3) + 2, how is the graph transformed?

Dvinal [7]

Answer:

f(x) is flipped, and each point is moved 3 units to the left and 2 units up

Step-by-step explanation:

8 0

3 years ago