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Tems11 [23]
3 years ago
13

Which equation is represented by the graph?

Mathematics
1 answer:
Trava [24]3 years ago
3 0

Answer:

y (x+1) this is your answer

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How many solutions can be found for the equation 4x + 5 = 10? (4 points)
VARVARA [1.3K]
Umm
I would say B) one
7 0
2 years ago
Read 2 more answers
The length of a rectangle is three times the width. The perimeter of the rectangle is at most 112cm. Which inequality models the
EleoNora [17]

Answer:

8x⩽112

Step-by-step explanation:

Width of the rectangle (in centimeters) = x

Therefore, the lenght of the rectable is 3x (in centimeters).  

The perimeter of the rectangle (in centimeters) is : 2x+2*3x=2x+6x=8x.

The perimeter of the rectangle is at most 112cm, therefore, 8x⩽112.

8 0
3 years ago
Help please i need this done by tmr !
Nataly [62]

Answer:

see explanation

Step-by-step explanation:

The sum of the 3 angles in a triangle = 180°

sum the 3 angles and equate to 180

5x + 7 + 4x + 2 + 90 = 180 , that is

9x + 99 = 180 ( subtract 99 from both sides )

9x = 81 ( divide both sides by 9 )

x = 9

Then

∠ ACB = 4x + 2 = 4(9) + 2 = 36 + 2 = 38°

∠ BAC = 5x + 7 = 5(9) + 7 = 45 + 7 = 52°

-----------------------------------------------------------------------

Since the triangles are congruent then corresponding angles are congruent , so

∠ B = ∠ E

6x + 10 = 70 ( subtract 10 from both sides )

6x = 60 ( divide both sides by 6 )

x = 10

5 0
3 years ago
What are the slope and the y-intercept of the graph of the linear function shown on the grid?
poizon [28]
Y-intercept looks like -1.5 and slope is -1/4
8 0
2 years ago
Calculate the total area of the shaded region.
LUCKY_DIMON [66]

so hmmm seemingly the graphs meet at -2 and +2 and 0, let's check

\stackrel{f(x)}{2x^3-x^2-5x}~~ = ~~\stackrel{g(x)}{-x^2+3x}\implies 2x^3-5x=3x\implies 2x^3-8x=0 \\\\\\ 2x(x^2-4)=0\implies x^2=4\implies x=\pm\sqrt{4}\implies x= \begin{cases} 0\\ \pm 2 \end{cases}

so f(x) = g(x) at those points, so let's take the integral of the top - bottom functions for both intervals, namely f(x) - g(x) from -2 to 0 and g(x) - f(x) from 0 to +2.

\stackrel{f(x)}{2x^3-x^2-5x}~~ - ~~[\stackrel{g(x)}{-x^2+3x}]\implies 2x^3-x^2-5x+x^2-3x \\\\\\ 2x^3-8x\implies 2(x^3-4x)\implies \displaystyle 2\int\limits_{-2}^{0} (x^3-4x)dx \implies 2\left[ \cfrac{x^4}{4}-2x^2 \right]_{-2}^{0}\implies \boxed{8} \\\\[-0.35em] ~\dotfill

\stackrel{g(x)}{-x^2+3x}~~ - ~~[\stackrel{f(x)}{2x^3-x^2-5x}]\implies -x^2+3x-2x^3+x^2+5x \\\\\\ -2x^3+8x\implies 2(-x^3+4x) \\\\\\ \displaystyle 2\int\limits_{0}^{2} (-x^3+4x)dx \implies 2\left[ -\cfrac{x^4}{4}+2x^2 \right]_{0}^{2}\implies \boxed{8} ~\hfill \boxed{\stackrel{\textit{total area}}{8~~ + ~~8~~ = ~~16}}

7 0
2 years ago
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