Answer:
.. ..
.. ..
Step-by-step explanation:
8/2=4
Answer:
Anything in the form x = pi+k*pi, for any integer k
These are not removable discontinuities.
============================================================
Explanation:
Recall that tan(x) = sin(x)/cos(x).
The discontinuities occur whenever cos(x) is equal to zero.
Solving cos(x) = 0 will yield the locations when we have discontinuities.
This all applies to tan(x), but we want to work with tan(x/2) instead.
Simply replace x with x/2 and solve for x like so
cos(x/2) = 0
x/2 = arccos(0)
x/2 = (pi/2) + 2pi*k or x/2 = (-pi/2) + 2pi*k
x = pi + 4pi*k or x = -pi + 4pi*k
Where k is any integer.
If we make a table of some example k values, then we'll find that we could get the following outputs:
- x = -3pi
- x = -pi
- x = pi
- x = 3pi
- x = 5pi
and so on. These are the odd multiples of pi.
So we can effectively condense those x equations into the single equation x = pi+k*pi
That equation is the same as x = (k+1)pi
The graph is below. It shows we have jump discontinuities. These are <u>not</u> removable discontinuities (since we're not removing a single point).
The first thing you do is subtract 2 from both sides to move the 2 to the left side
3-6x=7x
now add 6x to both sides to move -6x to the right
3=13x
divide by 13 to eliminate the 13 on the right side
3/13
Answer:
16/3 or 5.33
Step-by-step explanation:
Cross multiply
4/1 * 3/4
4 * 4 = 16
3 * 1 = 3
There's an infinite number of ways we can rewrite 16 3/4, some of them being:
16 3/4
16 6/8
16 12/16
16 24/32
16.75
67/4
335/20
670/40
etc.
I hope it will help you ;)