The factors of 49 are: 1, 7 and 49.
The factors of 50 are: 1, 2, 5, 10, 25 and 50.
The common factor is 1.
The <em><u>correct answer</u></em> is:
$236
Explanation:
Her annual property taxes are $1200. This means her escrow each month needs to have 1/12 of that amount; 1200/12 = $100 needs to be in the account each month.
Her mortgage insurance is $66 per month; this means a total of $100+66 = $166 needs to be in escrow every month.
Her homeowner's insurance is $840 per year; this means 1/12 of that needs to be in her escrow account each month:
840/12= 70
This gives us a total of $166+$70 = $236
Use formula: y-y1/x-x1=m(gradient)
so, y=-14x-1
m=-14
y-0/x-2=14/1
y=-14x+28
Answer:
Since the calculated value of z= 3.101 falls in the critical region it is concluded that average level of the chemical is greater than 12.50. The null hypothesis is rejected. There is evidence that the chemical plant is in violation of the working code.
Step-by-step explanation:
Here
The population mean = u= 12.50
The sample mean = x`= 14.83
The sample size= n= 15
Sample standard deviation= 2.91
Let the null and alternate hypotheses be
H0 : u ≤ 12.50 against the claim that Ha: u > 12.50
Applying z- test
z= x`-u/s/√n
Z= 14.83-12.5/ 2.91/√15
Z= 2.33/ 0.751
z= 3.101
The significance level is chosen to be 0.05
The critical value of z at 0.05 > 1.645 for one tailed test
Since the calculated value of z= 3.101 falls in the critical region it is concluded that average level of the chemical is greater than 12.50. The null hypothesis is rejected. There is evidence that the chemical plant is in violation of the working code.
