Honestly i just wanted to try this question since ive never seen it but i dont rlly know if i did it right at all
I equaled GH, HI, and GI together to get y
which i got y=-2
and what i got next i feel is off since
GH, HI, and GI all equaled -11
if you kind of know how to do the question maube you could correct me from there but otherwise dont take my word for it completely
So what we do is
area that remains=total area-triangle area that was cut out
we need to find 2 things
total area
triangle area
total area=rectange=base times height
area=(3x+4) times (2x+3)
FOIL or distribute
6x^2+8x+9x+12=6x^2+17x+12
triangle area=1/2 times base times height
triangle area=1/2 times (2x+2) times (x-2)=
(x+2) times (x-2)=x^2+2x-2x-4=x^2-4
so
total area=6x^2+17x+12
triangle area=x^2-4
subtract
area that remains=total area-triangle area that was cut out
area that remains=6x^2+17x+12-(x^2-4)=
6x^2+17x+12-x^2+4=
6x^2-x^2+17x+12+4=
5x^2+17x+16
area that remains is 5x^2+17x+16
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You would need one because you arent yet to 20 so it takes one tenth for example;
1.7 or 7/10
Thats my guess tho man if it is more complicated than that, SORRRYYYY
I think what your asking for is that x=10
