Answer: they are not perpendicular
Step-by-step explanation:
For the two equation to be perpendicular, the product of their slope must equals - 1.
We must made the equation to look like this
y = mx + c
Where m is the slope.
Now we shall find the slope of the individual equation as follows:
3/125x - y/5 = 1
Multiply through by 5 to make the coefficient of y to be 1, we have:
5(3/125x) - 5(y/5) = 5(1)
3/25x - y = 5
Now, Make y the subject, we have:
3/25x - y = 5
3/25x - 5 = y
Re-arranging, we have:
y = 3/25x - 5
Therefore the slope(m1) = 3/25
Now let us find the slope for the second equation
25/3x - y + 1= 0
Make y the subject, we have:
25/3x - y + 1= 0
25/3x + 1 = y
Re-arranging, we have:
y = 25/3x + 1
The slope(M2) = 25/3
Let us find the product of m1 and m2:
m1 x m2 = 3/25 x 25/3 = 1
Since the product of the slopes did not result to - 1, the equation are not perpendicular.
