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Alla [95]
3 years ago
9

Determine the independent and dependent variable from the following equations:

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
3 0

Answer:

a)  independent variable x, dependent variable y

b) independent variable s, dependent variable g

c) independent variable q, dependent variable p

d) independent variable n, dependent variable m

You might be interested in
Evaluate x-y/5 when x is 23 more than 3 times y and y=6
posledela

Answer:

7

Step-by-step explanation:

1) "x is 23 more than 3 times y" is the same thing as "x = 23 + 3y"

REMEMBER: when you see "is" replace is with an equals sign.

2) Solve for x with your new equation.

3) Plug 6 into the y ("y = 6")

x = 23 + 3 x 6... x = 23 + 18... x = 41

4) Plug in your variables, and evaluate.

(41 - 6)/5... 35/5... 7!

8 0
3 years ago
Suppose y varies directly as x, and y = 21 when x = 3. Find x when y = 42.
nata0808 [166]

Answer:

x = 24

Step-by-step explanation:

y₂ - y₁

42 - 21 = 21

x + 21

3 + 21 = 24

So when y increases by 21, so does x.

x = 24

7 0
3 years ago
How do you work this out?
Katarina [22]
Because ABCD is a rectangle, the length of CD is 12 cm.

We need to determine the length of DE.  If we can do that, then the sum of the lengths of CD and DE represents the unknown:  the length of CE.

To find the length of CE, we have to "solve" the upper triangle.

Here's an outline of what to do:

1.  Show that BC=AD and find the length.
2.  Note that angle CAD is 60 degrees.  Why?
3.  Note that angle EAD is 30 degrees.  Why?
4.  Find the length of ED
5.  Add ED and DC, that is, ED + 12 cm.  This is your answer.

Please ask questions if need be.
5 0
3 years ago
2people answer thiss . for points??!?!
beks73 [17]
???????????????????????????????????
5 0
3 years ago
Read 2 more answers
John left the museum and drove south at a rate of 55 mph. Sally left four hours later driving 10 mph faster than John in an effo
Leona [35]

Answer:

22 hours (B)

Step-by-step explanation:

John's velocity = 55mph

Sally's velocity = 65mph

John's time taken = x

Sally's time taken = x - 4

since they must cover the same distance.

and, distance = vel × time

Sally's vel × time = John's vel × time

55x = 65(x-4)

55x = 65x - 220

-10x = -220

x = 22 hours.

Therefore, Sally catches up after 22 hours

5 0
3 years ago
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