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sergey [27]
2 years ago
9

In order to make the expression below equivalent to 1 2 x 6, which additional operation should be included in the expression? Us

e the drop-down menu to select the operation. Five-fourths x 6.
Mathematics
1 answer:
marysya [2.9K]2 years ago
7 0

The additional operation which needed to make the expression equivalent to given expression is -\dfrac{3}{4} x. Thus the option 3 is the correct option.

<h3>What is equivalent expression?</h3>

Equivalent expression are the expression whose result is equal to the original expression, but the way of representation is different.

Given information-

The equation given in the problem is,

\dfrac{5}{4} x+6

Let the equation is equation number 1.

This expression is to convert in the expression, which is,

\dfrac{1}{2}x+6

Let the above equation is equation number 2.

Let the additional operation which needed to make the expression equivalent to given expression is f(x).

As the addition of f(x) and equation 1 is equal to the equation 2. Therefore,

f(x)+\dfrac{5}{4} x+6=\dfrac{1}{2}x+6

Solve the equation as,

f(x)=\dfrac{1}{2}x+6-\dfrac{5}{4} x-6\\f(x)=\dfrac{1}{2}x-\dfrac{5}{4} x\\f(x)=\dfrac{2-5}{4} x\\f(x)=\dfrac{-3}{4} x

Hence, the additional operation which needed to make the expression equivalent to given expression is -\dfrac{3}{4} x. Thus the option 3 is the correct option.

Learn more about the equivalent expression here;

brainly.com/question/2972832

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3 0
3 years ago
Solve |x – 4| + 6 = 17.
const2013 [10]

Answer:

\mathrm{C)\:}x=15,\:-7

Step-by-step explanation:

For |a-b|=c, there are two possible cases:

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Solving for both cases, we get:

\begin{cases}x-4+6=17, \:x+2=17, \: \fbox{$x=15$}\\-(x-4)+6=17,\: -x+10=17, \: -x=7, \:, \fbox{$x=-7$}\\\end{cases}

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3 years ago
A wire was bent into the shape of a rectangle with width 5 and length 7 . If this wire
12345 [234]

Answer:

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2(5) 2(7) = 24

If a square has 4 sides, put 24 as the numerator and 4 as the denominator.

24/4

Now, divide it and you'll get 6, the answer.

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3 years ago
In this problem, we're going to explain why any trapezoid that can be inscribed in a circle must be an isosceles trapezoid. In t
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So, think:


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x = 5^{5-2}

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4 0
3 years ago
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