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ratelena [41]
3 years ago
10

A tent in the shape of a triangle prism is made using the following piece of fabric.

Mathematics
1 answer:
ser-zykov [4K]3 years ago
3 0

Answer:

85.84 ft²

Step-by-step explanation:

The surface area of the fabric would be the total net area of the shape of the tent covered.

Thus, surface area = area of the 3 rectangular faces + area of the 2 triangular faces

From the diagram given, the 3 rectangular faces have the same dimensions as follows:

L = 6ft

W = 4ft

Area of the 3 rectangular faces = 3(6*4) = 3(24) = 72ft²

The 2 triangular faces have the same dimensions as follows:

B = 4f

H = 3.46ft

Area of the 2 triangular faces = 2(½*B*H)

= 2(½*4*3.46)

= 2(2*3.46)

= 2(6.92)

= 13.84 ft²

Surface area of fabric used to cover the triangular tent = 72ft² + 13.84ft² = 85.84 ft²

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Dustin has only nickels and quarters in his piggy bank. He has 49 coins total for a combined value of $8.85. How many of each ty
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Well obviously quarters equal 25 cents.  So you have to divide the 8.85 by 25 first.  That means he could have 35 quarters.  That least the rest as being dimes.  So find the remaining amount of the 8.85.  If you have 35 quarters that's $8.75.  And 8.85 minus 8.75 is 10 cents.  which would be 2 nickels.  That only adds up 37 coins.  So you break down one of the 25.  That would mean 5 more coins could be nickels.  Add 37 and 5 to get 42.   Do it again.  25 cents in nickels would be 5 more coins.  would be 46.  that would be missing 2 coins. But don't forget you're also subtracting from the 35 quarters. Now you would technically have 12 nickels and 33 quarters.  So you can do it one more time.  32 quarters means there is $8 in quarters at this point.

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So 17 nickels, 32 quarters to equal 49 coins and $8.85

(sorry some of it got mixed up above because I was forgetting to subtract the quarters from the total as I changed them to nickels, so pay attention to the end)
8 0
3 years ago
Plssss help quick i need it for sum important
Vanyuwa [196]

(a) The product of (2x-4)\ and\ (3x^2-x+4)  is calculated to be =6x^3-14x^2+12x-16

(b)The product of (2x-4) \ and\ (3x^2-x+4)\ is not equal to the product of  (4x-2)\ and\ (3x^2-x+4)

<u>Step-by-step explanation:</u>

<u>(a)</u>

(2x-4)(3x^2-x+4)\\\\=(2x.3x^2)+(2x.-x)+(2x.4)+(-4.3x^2)+(-4.-x)+(-4.4)\\\\=6x^3-2x^2+8x-12x^2+4x-16\\\\=6x^3-14x^2+12x-16

b)

(4x-2)(3x^2-x+4)\\\\=(4x.3x^2)+(4x.-x)+(4x.4)+(-2.3x^2)+(-2.-x)+(-2.4)\\\\=12x^3-4x^2+16x-6x^2+2x-8\\\\=12x^3-10x^2+18x-8

The product of (2x-4) \ and\ (3x^2-x+4)\ is not equal to the product of  (4x-2)\ and\ (3x^2-x+4)

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