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2 years ago

Find the area of the figure

Mathematics

1 answer:

Aneli [31]2 years ago

8 0

Answer:

area=18

Step-by-step explanation:

draw a dotted line so it separates the top part from the bottom and then the area of the bottom part is 6x2 which is 12 and then the area of the top is 3x2 which is 6

6+12=18

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I need help fast pleasee

trapecia [35]

Answer:

y = - cos ( $\frac{3}{4}$ x + $\frac{\pi }{4}$ )

Step-by-step explanation:

y = A cos ( Bx + C) + D

Vertical shift D = 0

A = - 1

Compression / Stretching B

Period of given function is $\frac{8\pi }{3}$

Period of cos x is 2π

$\frac{8\pi }{3}$ = $\frac{2\pi }{B}$ ⇒ B = $\frac{3}{4}$

Horizontal shift is C ÷ B

Horizontal shift of given function is $\frac{\pi }{3}$

$\frac{\pi }{3}$ = C ÷ $\frac{3}{4}$ ⇒ C = $\frac{\pi }{4}$

So, the equation of given function is

y = - cos (  $\frac{3}{4}$  x +  $\frac{\pi }{4}$  ) 

4 0

1 year ago

Each set of (x, y) values represent a set of equivalent ratios. Find the ratio of x to y for each set to determine which set des

Assoli18 [71]

Answer: The correct set is choice D.

We are looking for the same ratio with the given set of measurements. So lets start by determine the ratio of nuts to raisins. It is 40.5 to 48.6 or reduced it is 5 to 6. If you divide the fraction, you get the decimal 0.83333.

Only one of the relationships given has the same ratio. It is choice D. 11 to 13.32 can be divided to get 0.83333.

5 0

2 years ago

Read 2 more answers

What is the slope of the line passing through the points (1, 2) and (5, 4)?

brilliants [131]

Answer:

slope = $\frac{1}{2}$

Step-by-step explanation:

Calculate the slope m using the slope formula

m = (y₂ - y₁ ) / (x₂ - x₁ )

with (x₁, y₁ ) = (1, 2) and (x₂, y₂ ) = (5, 4)

m = $\frac{4-2}{5-1}$ = $\frac{2}{4}$ = $\frac{1}{2}$

8 0

2 years ago

Read 2 more answers

Lim x approaches 0 (1+2x)3/sinx

jok3333 [9.3K]

Interpreting your expression as

$\dfrac{3(1+2x)}{\sin(x)}$

when $x$ approaches zero, the numerator approaches 3:

$3(1+2x) \to 3(1+2\cdot 0) = 3(1+0) = 3\cdot 1 = 3$

The denominator approaches 0, because $\sin(0)=0$

Moreover, we have

$\displaystyle \lim_{x\to 0^-} \sin(x) = 0^-,\quad \displaystyle \lim_{x\to 0^+} \sin(x) = 0^+$

So, the limit does not exist, because left and right limits are different:

$\displaystyle \lim_{x\to 0^-} \dfrac{3(1+2x)}{\sin(x)}= \dfrac{3}{0^-} = -\infty,\quad \displaystyle \lim_{x\to 0^+}\dfrac{3(1+2x)}{\sin(x)}= \dfrac{3}{0^+} = +\infty$

8 0

2 years ago

Simplify -8y + 4(11y - 3)

erica [24]

-8y + 4(11y - 3) =
-8y + 44y - 12 =
36y - 12 <==

4 0

3 years ago