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3 years ago

When Michael was 10 years old, Sam was 14. Sam is now 28 and Michael is 24.

Mathematics

1 answer:

SpyIntel [72]3 years ago

6 0

Answer:

4 years difference

Step-by-step explanation:

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In △DEF, DF = 17 and m∠F=32. Find DF to the nearest tenth.

SSSSS [86.1K]

FE=14.42
ED=9.01
angle D=58
hope this helps

8 0

3 years ago

What is the value of AAA when we rewrite \left(\dfrac {6}{17}\right)^{9x}( 17 6 ) 9x (, start fraction, 6, divided by, 17, end

sineoko [7]

We have been given an expression $\left(\dfrac {6}{17}\right)^{9x}$ . We are asked to find the value of A when rewrite our given expression as $A^{x}$ .

To solve our given problem, we will use exponent properties.

Using exponent property $a^{mn}=(a^m)^n$ , we can rewrite our given expression as:

$\left(\dfrac {6}{17}\right)^{9x}=\left(\left(\dfrac {6}{17}\right)^9\right)^{x}$

Now, we will compare our expression with $A^{x}$ .

Upon comparing $\left(\left(\dfrac {6}{17}\right)^9\right)^{x}$ with $A^{x}$ , we can see that $A=\left(\dfrac {6}{17}\right)^9$ .

Therefore, the value of A is $\left(\dfrac {6}{17}\right)^9$ .

We can further simplify $\left(\dfrac {6}{17}\right)^9$ as:

$\left(\dfrac {6}{17}\right)^9=\frac {6^9}{17^9}=\frac{10077696}{118587876497}$

6 0

3 years ago

Evaluate -8a - b if a = 10 and b = 6

ss7ja [257]

The answer is -86 .....

3 0

3 years ago

The savings account offering which of these APRs and compounding periods offers the best APY?

zzz [600]

$\bf \qquad \qquad \textit{Annual Yield Formula}
\\\\
~~~~~~~~~~~~\textit{4.0784\% compounded monthly}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0784\%\to \frac{4.0784}{100}\to &0.040784\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{monthly, thus twelve}
\end{array}\to &12
\end{cases}
\\\\\\
\left(1+\frac{0.040784}{12}\right)^{12}-1\\\\
-------------------------------\\\\
~~~~~~~~~~~~\textit{4.0798\% compounded semiannually}\\\\
$

$\bf ~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0798\%\to \frac{4.0798}{100}\to &0.040798\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{semi-annually, thus twice}
\end{array}\to &2
\end{cases}
\\\\\\
\left(1+\frac{0.040798}{2}\right)^{2}-1\\\\
-------------------------------\\\\
$

$\bf ~~~~~~~~~~~~\textit{4.0730\% compounded daily}\\\\
~~~~~~~~~~~~\left(1+\frac{r}{n}\right)^{n}-1
\\\\
\begin{cases}
r=rate\to 4.0730\%\to \frac{4.0730}{100}\to &0.040730\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{daily, thus 365}
\end{array}\to &365
\end{cases}
\\\\\\
\left(1+\frac{0.040730}{365}\right)^{365}-1$

7 0

3 years ago

Read 2 more answers

The sloped roof of a house that is right beside its property line can be represented by the inequality −|x − 2| + 9 > 6. Solv

lesya692 [45]

Answer:

This Is CORRECT

Step-by-step explanation:

8 0

3 years ago

When Michael was 10 years old, Sam was 14. Sam is now 28 and Michael is 24.​

When Michael was 10 years old, Sam was 14. Sam is now 28 and Michael is 24.