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3 years ago

-3/4 x (-12)= I need help please this is hard

Mathematics

2 answers:

Arte-miy333 [17]3 years ago

7 0

Answer:

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photoshop1234 [79]3 years ago

3 0

Answer:

Step-by-step explanation:

Hope this helps and have a great day : )

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URGENT I HAVE ALMOST 0 TIME LEFT I NEED LAST MINUTE HELP

jonny [76]

Answer:

The zeros are the points where the parabola intercepts the x-axis.

$\sf x = 7 \implies x - 7 = 0$

$\sf x = 1 \implies x - 1 = 0$

$\sf \implies y = a(x - 7)(x - 1)$ where a is some constant

If the parabola passes through point (3, 4) then:

$\sf \implies a(3 - 7)(3 - 1) = 4$

$\sf \implies a(-4)(2) = 4$

$\sf \implies -8a = 4$

$\sf \implies a = -\dfrac12$

So the equation of the parabola is:

$\sf y = -\dfrac12(x - 7)(x - 1)$

Or in standard form:

$\sf y = -\dfrac12x^2+4x-\dfrac72$

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2 years ago

Solve 18q – 2q2 = 0<br>

3241004551 [841]

Answer:q=9

Step-by-step explanation:

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4 years ago

Read 2 more answers

1.<br> Write a polynomial function in factored form with zeros at -2, 5, and 6.

Hatshy [7]

Answer:

f(x) = (x + 2) (x − 5) (x − 6)

Step-by-step explanation:

f(x) = (x − (-2)) (x − 5) (x − 6)

f(x) = (x + 2) (x − 5) (x − 6)

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3 years ago

Let a be a real number and n a positive integer . show that x-a is a factor of x^n- a^n

nikklg [1K]

Answer:

steps below

Step-by-step explanation:

x-a=0

x=a plug in xⁿ - aⁿ

xⁿ - aⁿ = aⁿ - aⁿ = 0

(x-a) must be a factor of xⁿ - aⁿ

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I'm tragically single just to put that out there

EastWind [94]

Same I hate tiktoc for showing me happy couples

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