Perpendicular lines intersect and form 4 right angles (90 degree angles)
Answer: x = 3
Step-by-step explanation:
First you need to start by adding positive 4x to both sides since the 4x is a negative. 4x + (-7x) = -3x. Then it is just simply -3x+2 = -7. Since 2 is a positive number subtract both both sides by 2. Then you should get -3x = -9. Then divide both sides by -3 and the answer is x = 3.
The true equations are 24 over 2 squared equals 50 minus 6 squared minus 8 and 56 divided by 8 plus 3 squared equals 2 times 2 cubed.
The equation one is given as
39- 3(6) = 6(10/4)+4
After solving we get,
39 - 18 = 15 +4
21 = 19
Which is not a true equation.
2nd equation we have
24/(2^2)=50 -6^2-8
24/4 = 50 -36 -8
6 = 50 - 44
6 = 6
which is a true equation.
3rd equation we have
56/8+3^2= 2(2^3)
7 +9 = 2(8)
16 = 16
which is true equation.
4th equation, we have
8^2-5^2 = 4^2-7
16-10 = 16-7
6 = 9
Which is not a true equation.
To know more about true equation,
brainly.com/question/25510910
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Based on the given values above, we can find the exchange rate by simply multiplying $100 by the given exchange rate figure of 900.50. And the answer for this one would be 90,050. Therefore, the rate that he would receive is 90,050. It is the third option. Hope this answers your question. Have a great day!
Answer:
- 0.80
- 0.289
- 0.20
- 0.711
Step-by-step explanation:
Given:
![P(S\cap F)=0.44\\P(S\cap F^{c})=0.13\\P(S^{c}\cap F^{c}) = 0.32\\P(S^{c}\cap F) = 0.11](https://tex.z-dn.net/?f=P%28S%5Ccap%20F%29%3D0.44%5C%5CP%28S%5Ccap%20F%5E%7Bc%7D%29%3D0.13%5C%5CP%28S%5E%7Bc%7D%5Ccap%20F%5E%7Bc%7D%29%20%3D%200.32%5C%5CP%28S%5E%7Bc%7D%5Ccap%20F%29%20%3D%200.11)
The rule of total probability states that:
![P(A) = P(A\cap B) + P(A\cap B^{c})](https://tex.z-dn.net/?f=P%28A%29%20%3D%20P%28A%5Ccap%20B%29%20%2B%20P%28A%5Ccap%20B%5E%7Bc%7D%29)
Compute the individual probabilities as follows:
![P(S) = P(S\cap F) + P(S\cap F^{c})\\=0.44+0.13\\0.57](https://tex.z-dn.net/?f=P%28S%29%20%3D%20P%28S%5Ccap%20F%29%20%2B%20P%28S%5Ccap%20F%5E%7Bc%7D%29%5C%5C%3D0.44%2B0.13%5C%5C0.57)
![P(S^{c}) = 1 - P(S)\\=1-0.57\\=0.43](https://tex.z-dn.net/?f=P%28S%5E%7Bc%7D%29%20%3D%201%20-%20P%28S%29%5C%5C%3D1-0.57%5C%5C%3D0.43)
![P(F) = P(S\cap F) + P(S^{c}\cap F)\\=0.44+0.11\\=0.55](https://tex.z-dn.net/?f=P%28F%29%20%3D%20P%28S%5Ccap%20F%29%20%2B%20P%28S%5E%7Bc%7D%5Ccap%20F%29%5C%5C%3D0.44%2B0.11%5C%5C%3D0.55)
![P(F^{c})=1-P(F)\\=1-0.55\\=0.45](https://tex.z-dn.net/?f=P%28F%5E%7Bc%7D%29%3D1-P%28F%29%5C%5C%3D1-0.55%5C%5C%3D0.45)
Conditional probability of an event A given B is:
![P(A|B)=\frac{P(A\cap B)}{P(B)}](https://tex.z-dn.net/?f=P%28A%7CB%29%3D%5Cfrac%7BP%28A%5Ccap%20B%29%7D%7BP%28B%29%7D)
- Compute the value of
:
![P(S|F)=\frac{P(S\cap F)}{P(F)}\\=\frac{0.44}{0.55}\\=0.80](https://tex.z-dn.net/?f=P%28S%7CF%29%3D%5Cfrac%7BP%28S%5Ccap%20F%29%7D%7BP%28F%29%7D%5C%5C%3D%5Cfrac%7B0.44%7D%7B0.55%7D%5C%5C%3D0.80)
- Compute the value of
![P(S|F^{c})](https://tex.z-dn.net/?f=P%28S%7CF%5E%7Bc%7D%29)
![P(S|F^{c})=\frac{P(S\cap F^{c})}{P(F^{c})}\\=\frac{0.13}{0.45}\\=0.289](https://tex.z-dn.net/?f=P%28S%7CF%5E%7Bc%7D%29%3D%5Cfrac%7BP%28S%5Ccap%20F%5E%7Bc%7D%29%7D%7BP%28F%5E%7Bc%7D%29%7D%5C%5C%3D%5Cfrac%7B0.13%7D%7B0.45%7D%5C%5C%3D0.289)
- Compute the value of
![P(S^{c}|F)=\frac{P(S^{c}\cap F)}{P(F}\\=\frac{0.11}{0.55}\\=0.20](https://tex.z-dn.net/?f=P%28S%5E%7Bc%7D%7CF%29%3D%5Cfrac%7BP%28S%5E%7Bc%7D%5Ccap%20F%29%7D%7BP%28F%7D%5C%5C%3D%5Cfrac%7B0.11%7D%7B0.55%7D%5C%5C%3D0.20)
- Compute the value of
![P(S^{c}|F^{c})=\frac{P(S^{c}\cap F^{c})}{P(F^{c})}\\=\frac{0.32}{0.45}\\=0.711](https://tex.z-dn.net/?f=P%28S%5E%7Bc%7D%7CF%5E%7Bc%7D%29%3D%5Cfrac%7BP%28S%5E%7Bc%7D%5Ccap%20F%5E%7Bc%7D%29%7D%7BP%28F%5E%7Bc%7D%29%7D%5C%5C%3D%5Cfrac%7B0.32%7D%7B0.45%7D%5C%5C%3D0.711)