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Elodia [21]
3 years ago
9

Help me please I will UPVOT

Mathematics
2 answers:
Art [367]3 years ago
8 0
Yes, that is true.

If x = y, x² = y².
If x = y, substitute x into where y is;

x² = y²
x² = (x)²
Thus, yes they will be.
Anon25 [30]3 years ago
4 0
<span>When you square each side of an equation then the resulting equation is not equivalent to the original</span>
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4(5x - 2) = 72<br> What do I do
Pepsi [2]

Answer:

x = 4

Step-by-step explanation:

4(5x - 2) = 72

Do the distributive property

20x - 8 = 72

Then add 8 to both sides to get 20x alone

20x - 8 = 72

      + 8  + 8

20x = 80

Then divide both sides by 20 to get x

\frac{20x}{20} = \frac{80}{20}

x = 4

6 0
3 years ago
Write the quadratic equation whose roots are 1 and −5, and whose leading coefficient is 4.
jarptica [38.1K]

Answer:

Standard Form: y = 4(x-1)(x+5)

Step-by-step explanation:

4 is the leading coefficient, so it should go in front. When making a standard quadratic equation, you must do the opposite for each of the roots (negative to positive, positive to negative.)

if you’re asking for a general form quadratic equation, then sorry, I am unable to help you with that :(

5 0
2 years ago
can someone help me understand this? The length of the rectangle is two more then its width. the perimeter of the rectangle is 7
Tema [17]

Answer:

length = 24 meters

Step-by-step explanation:

1. l = 2w

2. P = 2l + 2w

P=72

3. 72 = 2l + 2w

4. Substitute w=l/2 to solve for l

72 = 2l + 2(l/2) ---> 72 = 3L - Divide by 3 on both sides

L= 24 meters

4 0
3 years ago
Question 2 options:
zloy xaker [14]
2. 7 PM
3. Mike went continuously towards his destination until hour 3. And the total time he went back home was three hours (hrs 8-11.)
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8 0
2 years ago
How do you find the holes, vertical, and horizontal asymptote of an equation?
AfilCa [17]
This is a great question, but it's also a very broad one.  Please find and post one or two actual rational expressions, so we can get started on specifics of how to find vertical and horiz. asymptotes.

In the case of vert. asy.:  Set the denom. = to 0 and solve for x.  Any real x values that result indicate the location(s) of vertical asymptotes.

4 0
3 years ago
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