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Evgen [1.6K]
3 years ago
14

The equatorial diameter of Jupiter is about 89,000 mi. This is about 11.23 times the equatorial diameter of earth. What is the e

quatorial diameter of earth? Round the nearest integer
Mathematics
1 answer:
Simora [160]3 years ago
6 0

The equatorial diameter of the earth is 7925 mi.

<u>Solution: </u>

Given, The equatorial diameter of Jupiter is about 89,000 mi.  

This is about 11.23 times the equatorial diameter of earth.  

We have to find what is the equatorial diameter of earth? Round the nearest integer

Now, according to given information,

Equatorial Diameter of Jupiter = 11.23 \times equatorial diameter of earth

\text { Then, equatorial diameter of earth }=\frac{\text { diameter of iupiter }}{11.23}

\begin{array}{l}{\text { equatorial diameter of earth }=\frac{89000 \mathrm{mi}}{11.23}} \\\\ {\text { equatorial diameter of earth }=7925.2003 \mathrm{mi}}\end{array}

Hence, the equatorial diameter of the earth is 7925 mi.

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Answer:

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We can rewrite this expression like this:

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And we can use the quadratic formula given by:

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And replacing we got:

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And solving we got:

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And since the value can't be negative the answer would be x = 32.75 and the value of y = 32.75+10 =42.75

Step-by-step explanation:

For this case we know that we have a rectangular playground and the area can be founded with this formula:

A = xy

Where x represent the width and y the length. From the problem we know that A =1400 m^2 and the heigth is 10m longer than the wide so we can write this condition as:

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And replacing this formula into the area we got:

1400 = x(x+10)= x^2 +10x

We can rewrite this expression like this:

x^2 +10 x -1400 =0

And we can use the quadratic formula given by:

x = \frac{-b \pm \sqrt{b^2 -4ac}}{2a}

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And replacing we got:

x = \frac{-10 \pm \sqrt{10^2 -4(10)(-1400)}}{2*1}

And solving we got:

x_1 =32.75 , x_2 = -42.75

And since the value can't be negative the answer would be x = 32.75 and the value of y = 32.75+10 =42.75

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