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Sphinxa [80]
3 years ago
7

What’s the answer I need an answer now if not I’m not using this app anymore

Mathematics
1 answer:
mario62 [17]3 years ago
3 0

Answer:

the answer to your problem is B

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(60 POINTS) PLEASE HELP ME!!!
Elan Coil [88]

Answer:

the second option

Step-by-step explanation:

The second option because there is no pattern.

8 0
4 years ago
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2. It takes 1 3/8 minutes to wrap a parcel and 1/2 minute to address it. How many minutes does it take to:
Drupady [299]

Answer:

45/2

Step-by-step explanation:

U first have to change the mixed number to improper fraction and find the least common multiple

8 0
3 years ago
A small animal can eat an amount of food that is equivalent to 2/5 it's body weight in 1/2 hour at this rate what fraction of it
Kruka [31]

Answer:

Step-by-step explanation:

Think:  2/5 its body weight in 1/2 hour immediately becomes 4/5 its body weight in 1 hour.  There's a proportional relationship here.

7 0
4 years ago
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Find the volume of a cylinder if the radius is 8cm and the height is 15cm?​
saul85 [17]

Answer:

3015.92894745 cm^3

Step-by-step explanation:

Formula for volume of cylinder(v)= πr^2h

Here,

r=8 cm

h=15cm

Now,

V=πr^2h=π8^2*15=π64*15=960π=3015.92894745 cm^3

8 0
3 years ago
Read 2 more answers
How to prove this???
swat32
\cos^3 2A + 3 \cos 2A \\
\Rightarrow \cos 2A (\cos^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (\cos^2 2A + 3)  \\
\Rightarrow (\cos^2 A - \sin^2 A) (1 - \sin^2 2A + 3) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - \sin^2 2A) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - (2\sin A \cos A)(2\sin A \cos A)) \\
\Rightarrow (\cos^2 A - \sin^2 A) (4 - 4\sin^2 A \cos^2 A) \\ 
\Rightarrow 4(\cos^2 A - \sin^2 A) (1 - \sin^2 A \cos^2 A) 


go to right side now

4( \cos^6 A - \sin^6 A)\\
\Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A)

use x^3 - y^3 = (x-y)(x^2 + xy + y^2) and x^3 + y^3 = x^2 - xy + y^2

4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4( \cos^3 A - \sin^3 A)(\cos^3 A + \sin^3 A) \\
\Rightarrow  4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\
~\quad  \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A)

so \sin^2 A + \cos^2 A = 1

4( \cos^6 A - \sin^6 A)\\ \Rightarrow 4(\cos A - \sin A)(\cos^2 A + \cos A \sin A + \sin^2 A) \\ ~\quad \quad\cdot ( \cos A + \sin A)(\cos^2 A - \cos A \sin A + \cos^2 A) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 + \cos A \sin A )(1- \cos A \sin A ) \\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \cos^2 A \sin^2 A )\\ \Rightarrow 4(\cos^2 A - \sin^2 A)(1 - \sin^2 A \cos^2 A ) \\
 \Rightarrow Left hand side
4 0
3 years ago
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