Let a,b,c be the sides of the triangle. Make c the longest side. The value of a and b doesn't matter.
a = 9
b = 40
c = 41
The value of a^2+b^2 is
a^2+b^2 = 9^2+40^2 = 1681
The value of c^2 is
c^2 = 41^2 = 1681
Because a^2+b^2 = c^2 for these values, this means that we have a right triangle.
Answer is choice D
Answer:
![12 \sqrt{2}](https://tex.z-dn.net/?f=12%20%5Csqrt%7B2%7D%20)
Step-by-step explanation:
Taking the terms one at a time,
![\frac{14}{ \sqrt{2} } \\ \frac{14 * \sqrt{2} }{ \sqrt{2} * \sqrt{2} } \\ \frac{14 \sqrt{2} }{2} \\ 7 \sqrt{2}](https://tex.z-dn.net/?f=%20%5Cfrac%7B14%7D%7B%20%5Csqrt%7B2%7D%20%7D%20%20%5C%5C%20%20%20%5Cfrac%7B14%20%2A%20%20%5Csqrt%7B2%7D%20%7D%7B%20%5Csqrt%7B2%7D%20%2A%20%20%5Csqrt%7B2%7D%20%20%7D%20%20%5C%5C%20%20%20%5Cfrac%7B14%20%20%5Csqrt%7B2%7D%20%7D%7B2%7D%20%20%5C%5C%20%207%20%5Csqrt%7B2%7D%20%20)
![\sqrt{50} \\ \sqrt{25 * 2} \\ \sqrt{25}* \sqrt{2} \\ 5 * \sqrt{2} \\ 5 \sqrt{2}](https://tex.z-dn.net/?f=%20%5Csqrt%7B50%7D%20%5C%5C%20%20%5Csqrt%7B25%20%2A%202%7D%20%5C%5C%20%20%5Csqrt%7B25%7D%2A%20%20%5Csqrt%7B2%7D%20%20%20%20%5C%5C%205%20%2A%20%20%5Csqrt%7B2%7D%20%20%20%5C%5C%205%20%5Csqrt%7B2%7D%20)
Adding the terms, you have;
![7 \sqrt{2} + 5 \sqrt{2} =(7 + 5) \sqrt{2} = 12 \sqrt{2}](https://tex.z-dn.net/?f=7%20%5Csqrt%7B2%7D%20%2B%205%20%5Csqrt%7B2%7D%20%3D%287%20%2B%205%29%20%5Csqrt%7B2%7D%20%3D%2012%20%5Csqrt%7B2%7D%20%20%20%20)
Hope it helps!
I'm out!
The sum of all the angles of any triangle is 180 degrees
--> Therefore the missing angle is:
<u>x = 180 - 60 - 75 = 45</u>
Hope that helps!
Answer:
there is no question
Step-by-step explanation:
Answer:
9.6e-5
Step-by-step explanation: