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Bas_tet [7]
3 years ago
8

Write the standard form of the equation of the circle with radius 4 and center (−7,−6).

Mathematics
1 answer:
olasank [31]3 years ago
4 0

The equation of a circle is written as (x-h)^2 +(y-k)^2 = r^2

h is the x value of the center and k is the y value of the center and r is the radius.

Replace h, k and r with the given information:

(x- -7)^2 + (y - -6)^2 = 4^2

Simplify:

(x+7)^2 + (y+6)^2 = 16

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The mass of a cat in grams is greater because in 1 gram=0.001 kilograms
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3 years ago
CAN SOMEONE HELP DO #1 PLEASE
love history [14]

Answer:

  B.  $450

Step-by-step explanation:

The amount of commission is the commission rate (3%) times the amount of sales to which it is applied ($5000). Garrett's commission last week would be ...

  0.03 × $5000 = $150

He is also paid $300 each week in addition to his commission, so his total pay last week was ...

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4 0
2 years ago
Find the area of the shape shown below.
cricket20 [7]

Answer:

18

Step-by-step explanation:

3+9=12

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3 0
3 years ago
Read 2 more answers
Find tan(450-a), If <br><img src="https://tex.z-dn.net/?f=%20%5Ctan%28a%29%20%3D%20%20%5Cfrac%7B1%7D%7B2%7D%20" id="TexFormula1"
Inessa05 [86]

Answer:

tan(450-a)=5\sqrt{3}-8

Step-by-step explanation:

We know that:

tan(a-b)=\frac{tan(a)-tan(b)}{1+tan(a)tan(b)}

tan(450-a)=\frac{tan(450)-tan(a)}{1+tan(450)tan(a)}

Remember:

450°=360°+60°

and:

tan(a)=\frac{1}{2}

Thus:

tan(450-a)=\frac{tan(60)-tan(a)}{1+tan(60)tan(a)}\\\\

Then:

tan(450-a)=5\sqrt{3}-8

4 0
2 years ago
Assume the world catch of fish in 1950 was 12 million tons and in 1955 it was 96 million tons.
Rama09 [41]

The rate of change is 16.8 million tons per year

<em><u>Solution:</u></em>

Given that, the world catch of fish in 1950 was 12 million tons and in 1955 it was 96 million tons

<em><u>The average rate of change is given by formula:</u></em>

\text{ Average rate of change } = \frac{\text{ change in value }}{\text{ number of years }}

Value in 1950 = 12 million tons

Value in 1955 = 96 million tons

Change in value = value in 1955 - value in 1950

Change in value = 96 million - 12 million = 84 million tons

Number of years = 1950 to 1955 = 5 years

<em><u>Substitute the given values in formula,</u></em>

<em><u></u></em>\text{ Average rate of change } = \frac{84 \text{ million tons}}{5} = 16.8 \text{ million tons}<em><u></u></em>

Thus rate of change is 16.8 million tons per year

5 0
3 years ago
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