Answer:
99% confidence interval for the population average examination score is between a lower limit of 69.2872 and an upper limit of 82.7128.
Step-by-step explanation:
Confidence interval = mean +/- margin of error (E)
mean = 76
variance = 144
sd = sqrt(variance) = sqrt(144) = 12
n = 25
degree of freedom (df) = n - 1 = 25 - 1 = 24
confidence level (C) = 99% = 0.99
significance level = 1 - C = 1 - 0.99 = 0.01 = 1%
t-value corresponding to 24 df and 1% significance level is 2.797
E = t×sd/√n = 2.797×12/√25 = 6.7128
Lower limit = mean - E = 76 - 6.7128 = 69.2872
Upper limit = mean + E = 76 + 6.7128 = 82.7128
99% confidence interval is (69.2872, 82.7128)
The first integer (x) is equal to the consecutive even integers, x+2, x+4.
x = (x+2) + (x+4)
x = 2x + 6
x - 6 = 2x
x = -6 (First integer)
+2
-4 (Second integer)
+4
-2 (Third integer)
Integers: -6, -4, -2
Equation: x = (x+2) + (x+4)
4,5,9,10
just add two to each number
Http://lbcsd.innersync.com/sites/jhayes/documents/U1M3Gr6pg.49-502015JHayes.pdf
Answer:
the answer is 312 hopes this helps
Step-by-step explanation:
the square root of 144 is 12
12+12^2 =?
12+144=156
156x6=936
936/3=?
312
