Question

Rationalise the denominator of 2sq3+3sq2/4sq3+sq2​

Answer 1

Answer:

$\frac{9+5\sqrt6}{23}$

Step-by-step explanation:

We can rewrite the fraction as

$\frac{2\sqrt{3}+3\sqrt{2}}{4\sqrt{3}+\sqrt{2}}$

In order to rationalize the denominator of such a complex fraction, we must multiply the fraction by the conjugate of the denominator. In this case, the conjugate of the denominator would be $4\sqrt{3}-\sqrt{2}$. Multiplying both sides of the fraction by the conjugate of the denominator would result in the fraction:

$\frac{9+5\sqrt6}{23}$