Answer:
468
Step-by-step explanation:
=13[42-6]
=13 (36)
=13×36
=468
Answer:
Null hypothesis: ∪ = No possible child abuse or neglect
Alternative hypothesis: Uₐ = Possible child abuse or neglect
Step-by-step explanation:
Null hypothesis: ∪ = No possible child abuse or neglect
Alternative hypothesis: Uₐ = Possible child abuse or neglect
A type I error occurs when you reject the null hypothesis when it is true. In this situation, a type I error occurs when you conclude on possible child neglect or abuse and place the child in protective custody
A type II error occurs when you accept the null hypothesis when it is false. In this instance, a type II error occurs when you conclude on no possible child abuse or neglect when there is and fail to remove the child from the home.
In this case, the type II error is the more serious error. Failure to remove the child when there is possible child abuse or neglect will lead to more detrimental effect. Although, the type I error is also serious, it is not so detrimental as the type II error.
Since we are given with the identity of the chemical as Carbon-14, we obtain the half-life of the chemical from a reliable source and get a value of 5730 years. The equation that we are going to use for this item is,
A(t)/A(0) = (0.50)^(n/5730)
where A(t) is the current amount, A(0) is the initial amount and n is the number of years. We know from the given that the ratio of A(t) and A(0) is equal to 0.63. Substituting this to the given,
0.63 = 0.50^(n/5730)
n = 3819.48
Thus, the sample is approximately 3819.5 years old.
Answer:
0,2,4,8
Step-by-step explanation:
:)
