The prallelogram whose adjacent sides are equal and one vertex angle is 90 degrees is a square.
The value of angle 1 is 90 degrees as the diagonal of the square intersect at 90 degrees.

The value of y is 23.
The diagonal of the square bisect the vertex angle hence the angle of 3x is 45 degrees.

Thus, the value of x is 15 degrees.
The value of 12z is 45 degrees.

Thus, the required value of z is 3.75 degrees.
Answer is no solution I believe
Answer:
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Given: <span>y = x^2 + 6x - 5. Then a = 1, b = 6 and c = -5.
The x-coord. of the vertex is given by x = -b / (2a), which here is x = -6 / (2*1) = -3.
Use the given formula </span><span>y = x^2 + 6x - 5 to find the value of y when x = -3:
y = (-3)^2 + 6(-3) - 5 = 9 - 18 - 5 = -14
Then the vertex is (-3, -14).</span>
Answer:
A
Step-by-step explanation: