Answer:
The pair of triangles that are congruent by the ASA criterion isΔ ABC and Δ XYZ.
The pair of triangles that are congruent by the SAS criterion is Δ BAC and ΔRQP.
Step-by-step explanation:
Two triangles are congruent by ASA property if any two angles and their included side are equal in both triangles .In triangles Δ ABC and Δ XYZ the equal side 5 is between the two equal angles. So these triangles are congruent by ASA criterion.
Two triangles are congruent by SAS if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle .In triangles Δ BAC and ΔRQP. the included angles A and Q are equal and hence the triangles are congruent by SAS criterion.
Answer:
an = 4/3n - 13/3.
Step-by-step explanation:
The first term is a1,
a24 = a1 + 23d
83/3 = a1 + 4/3* 23
a1 = 83/3 - 92/3
a1 = -9/3 = -3.
So the nth term an = -3 + 4/3(n - 1)
an = -3 + 4/3 n - 4/3
an = 4/3n - 13/3
We look for the minimum of each function.
For f (x) = 3x2 + 12x + 16:
We derive the function:
f '(x) = 6x + 12
We match zero:
6x + 12 = 0
We clear the value of x:
x = -12/6
x = -2
We substitute the value of x in the equation:
f (-2) = 3 * (- 2) ^ 2 + 12 * (- 2) + 16
f (-2) = 4
For g (x) = 2sin(x-pi):
From the graph we observe that the minimum value of the function is:
y = -2
Answer:
A function that has the smallest minimum y-value is:
y = -2
Answer:
The home would be worth $249000 during the year of 2012.
Step-by-step explanation:
The price of the home in t years after 2004 can be modeled by the following equation:
In which P(0) is the price of the house in 2004 and r is the growth rate.
Since 2003 median home prices in Midvale, UT have been growing exponentially at roughly 4.7 % per year.
This means that 
$172000 in 2004
This means that 
What year would the home be worth $ 249000 ?
t years after 2004.
t is found when P(t) = 249000. So
2004 + 8.05 = 2012
The home would be worth $249000 during the year of 2012.
Answer:
Step-by-step explanation:
WHEN ADDING TWO LOGS TO COMPRESS THEM YOU MULTIPLY THE TERMS
LOG(4^2)(2^3)
LOG(16)(8)
LOG(128)
