<span>So you have composed two functions,
</span><span>h(x)=sin(x) and g(x)=arctan(x)</span>
<span>→f=h∘g</span><span>
meaning
</span><span>f(x)=h(g(x))</span>
<span>g:R→<span>[<span>−1;1</span>]</span></span>
<span>h:R→[−<span>π2</span>;<span>π2</span>]</span><span>
And since
</span><span>[−1;1]∈R→f is defined ∀x∈R</span><span>
And since arctan(x) is strictly increasing and continuous in [-1;1] ,
</span><span>h(g(]−∞;∞[))=h([−1;1])=[arctan(−1);arctan(1)]</span><span>
Meaning
</span><span>f:R→[arctan(−1);arctan(1)]=[−<span>π4</span>;<span>π4</span>]</span><span>
so there's your domain</span>
1.) 3+2=? ?=5 brothers 2.) 54+9=? ?=63 students 3.) 15-9=? ?=4
4.) 60-20=? ?=40 children 5.) 50-15=? ?=35 trees 6.) 14+4=? ?=18 times
Don't know why you needed help with this but ok.
Answer:
no comprehendo
Step-by-step explanation:
Answer:
Most people tend to screen shot
Step-by-step explanation:
