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REY [17]
3 years ago
9

Sheila can ride her bicycle 6000 meters in 15 minutes. How far can she ride her bicycle in 2 minutes.

Mathematics
2 answers:
trapecia [35]3 years ago
8 0

Answer:

Step-by-step explanation:

800 meters

taurus [48]3 years ago
3 0

Answer: about 500

Step-by-step explanation:

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Can I have help on this?<br><br><br>​
AysviL [449]

Answer:

25°

Step-by-step explanation:

51+x+14=90°

x+65=90°

x=90-65

x=25°

6 0
2 years ago
Find the axis of summetry and the Vertex of its graph. Y=x2/squared-8x
Vilka [71]

Answer:

Direction: Opens Up

Vertex:

(

4

,

−

18

)

(4,-18)

Focus:

(

4

,

−

71

4

)

(4,-714)

Axis of Symmetry:

x

=

4

x=4

Directrix:

y

=

−

73

4

y=-734

Select a few

x

x values, and plug them into the equation to find the corresponding

y

y values. The

x

x values should be selected around the vertex.x

y

2

−

14

3

−

17

4

−

18

5

−

17

6

−

14

xy2-143-174-185-176-14

Graph the parabola using its properties and the selected points.

Direction: Opens Up

Vertex:

(

4

,

−

18

)

(4,-18)

Focus:

(

4

,

−

71

4

)

(4,-714)

Axis of Symmetry:

x

=

4

x=4

Directrix:

y

=

−

73

4

y=-734

x

y

2

−

14

3

−

17

4

−

18

5

−

17

6

−

14

xy2-143-174-185-176-14

image of graph

3 0
3 years ago
A salesman packs dog biscuits in boxes containing 16, 17, 23, or 24 pounds each. He will not sell them in any other sizes or spl
sweet [91]

Answer:

the closest the sales man can fit in a box is 96lbs without going over. so therefore, no, he cannot fulfill the order.

5 0
3 years ago
You have a nightlight plugged into an outlet in the hallway, which uses 3.5 watts when plugged in. If the house circuit provides
Bess [88]
This problem can be solved by manipulating the formula for power, which is: P = VI. Where:

P = Power in watts
V= Voltage in volts
I = Current in amperes

Since we are already given the power and voltage, simple substitution can be done.

P = VI
3.5 watts = 120 volts * I
I = 3.5 / 120
I = 0.0292 Amperes or 29.2 milliAmperes

Therefore, the current through the bulb is 29.2mA
5 0
3 years ago
How far is a chord of length 8 cm from the centre of a circle of radius 5 cm
ivann1987 [24]
  • Answer:

<em>OB = 3 cm</em>

  • Step-by-step explanation:

<em>AO = radius = 5 cm</em>

<em>AB = 8cm/2 = 4 cm</em>

<em>Pythagora</em>

<em>OB² = AO² - AB²</em>

<em>= (5cm)² - (4cm)²</em>

<em>= 25cm² - 16cm²</em>

<em>= 9 cm²</em>

<em>OB = √9cm²</em>

<em>= 3 cm</em>

8 0
3 years ago
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